According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.
<h3>How many children went to the movie theatre?</h3>
In this question we have a <em>word</em> problem, whose information must be translated into <em>algebraic</em> expressions to find a solution. Let be x and y the number of children and adults that went to the movie theatre, respectively.
We need two <em>linear</em> equations, one for the number of people assisting to the theatre and another for the total sales:
x - 4 · y = 0 (1)
6.30 · x + 9.50 · y = 1063.20 (2)
By algebraic procedures the solution to this system is: x = 122.559, y = 30.639. Since the number of tickets sold are integers, then we truncate each result: x = 122, y = 30.
According to the characteristics of <em>ticket</em> sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.
To learn on systems of linear equations: brainly.com/question/27664510
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Plural for index you are wecome bud
To solve this problem, start by plugging in your given n value.
This results in:
k = 100 - 4(60)
Next, simplify the parentheses by multiplying the -4 and the 60 together.
This leaves you with:
k = 100 - 240
To simplify for k, subtract 240 from 100 to get:
k = -140
So your final answer is k = -140 when n = 60
C^2=a^2+b^2
6^2=5^2+b^2
36=25+b^2
b^2=36-25
b^2=11
b= √11
b=3.3166
If you need to round it to the tenth place,
b~3.3
to hundreds place,
b~3.32
Good luck
If $36 is 3/4 of the total cost, then you can divide 36 by 3 to get the answer for what 1/4 of the cost is. 36 divided by 3 is 12. 12 times 4 is 48. the cost is $48.
