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Juli2301 [7.4K]
3 years ago
9

Will give brainliest answer!

Mathematics
1 answer:
kifflom [539]3 years ago
8 0
5x + 60y = 35

x +y = 1.5 : rewrite as x = 1.5-y   and substitute this formula for x in the first one:

5(1.5-y) + 60y = 35

distribute:

7.5 - 5y + 60y = 35

combine like terms:

7.5 + 55y = 35

subtract 7.5 from both sides:

55y = 27.5

divide both sides by 55 to solve for  y

y = 27.5 / 55 = 0.5

now substiute 0.5 for y in the 2nd equation:

x + 0.5 = 1.5

x = 1.5 - 0.5 = 1

 he walked for 1 hour


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NO LINKS!! Please help me with this problem​
Vera_Pavlovna [14]

Information : The given hyperbola is a horizontal hylerbola with its centre (3 , -5) and one of its focus at (9 , -5) and vertex at (7 , -5) and as we can see that the focus and vertex have same y - coordinates, it must have its Transverse axis on line y = - 5.

Now,

it's vertex is given, I.e (7 , -5)

so, length of semi transverse axis will be equal to distance of vertex from centre, i.e

  • a = 7 - 3 = 4 units

Now, it's focus can be represented as ;

\qquad \sf  \dashrightarrow \: (3 + ae,  - 5 )

so,

  • ae + 3 = 9

and we know, a = 4

\qquad \sf  \dashrightarrow \: 4e + 3 = 9

\qquad \sf  \dashrightarrow \: 4e = 6

\qquad \sf  \dashrightarrow \: e =  \cfrac{3}{2}

Now, let's find the measure of semi - conjugate axis (b)

\qquad \sf  \dashrightarrow \:  {b}^{2}  =  {a}^{2} ( {e}^{2}  - 1)

\qquad \sf  \dashrightarrow \:  {b}^{2}  = 16( \frac{9}{4}  - 1)

\qquad \sf  \dashrightarrow \:  {b}^{2}  = 16( \frac{9 - 4}{4}  )

\qquad \sf  \dashrightarrow \:  {b}^{2}  = 16( \frac{5}{4}  )

\qquad \sf  \dashrightarrow \:  {b}^{2}  = 20

\qquad \sf  \dashrightarrow \: b =   \sqrt{20}

So, it's time to write the equation of hyperbola, as we already have the values of a and b ~

\qquad \sf  \dashrightarrow \:  \cfrac{ {(x - h)}^{2} }{ {a}^{2} }  -  \cfrac{( {y  - k)}^{2} }{ {b}^{2} }  = 1

[ plug in the values, and h = x - coordinate of centre, and k = y - coordinate of centre ]

\qquad \sf  \dashrightarrow \:  \cfrac{ ({x-3)}^{2} }{ {16}^{} }  -  \dfrac{ {(y+5)}^{2} }{ { {20} }^{} }  = 1

6 0
2 years ago
Read 2 more answers
.
babunello [35]
<span>From the problem, you can get this equation:
Jane is 2 years older than Sally
J=z+2
David is 4 times older than Jane.
D=4J

</span>Write two equivalent expressions that represent David’s age in terms of Sally’s age, z, and explain how the two expressions relate to one another.<span>Sally is z years old.
From the 2 equation above, you can get:
</span>D=4J
D=4(z+2)
D=4z+8

D-8=4z
(D-8)/4=z
The two equivalent expression would be D=4z+8 and (D-8)/4=z

The expression that more usefull would be D=4z+8 if you want to determine David age.
4 0
4 years ago
Find the area of a triangle: base 14 cm, height 5.5 cm
Sloan [31]
Area of a triangle= 1/2bh
14x5.5=77
77/2=38.5cm^2
3 0
3 years ago
A company that manufactures cell phones has been given a quarterly operating budget of $1,620,151.13. The company's quarterly op
monitta

Answer:

A

Step-by-step explanation:

Set up equation

76.19x + 292388 + 1620151.13

Subtract 292,388 from 1,620,151.13

76.19x  + 292388 - 292388 = 1620151.13 - 292388

76.19x = 1327763.13

Divide

\frac{76.19x}{76.19}  =  \frac{1327763.13}{76.19}

x = 17427

5 0
4 years ago
The diagonal of a rectangle is 25 in. The width is 15 in. What is the area of the rectangle
djyliett [7]
Here is your answer > >

Width of rectangle =15 inches

Length of rectangle =?

Diagonal of rectangle = 25 inches

We know that

(Diagonal of rectagle)^2=length^2+breadth^2

(25)^2=l^2+(15)^2

625=l^2+225

l^2=625-225

l^2=400

l=Root 400

l=20 inches

Hope it helps!

Thankyou ☆ ☆

Bebrainly
6 0
3 years ago
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