So lets just assume that y = 1 since 2x is most likely an even number.
Then we can say that 2x = 8
8 divided by 2 is 4
so a point on this line could be (4,1)
Hope this helped
Answer:
13.13
Step-by-step explanation:
39.39 ÷ 3
13.13
There is not a lot of work
Looking at it we can tell that 3 will go into 3 one time, and 3 will go into 9 three times because:
1 x 3 = 3
3 x 3 = 9
You first subtract 1/5 from both sides
3/4-1/5 = 11/20
3/2x=11/20
now you multiply 2/3 on both sides since you have to get x
11/20 * 2/3
x = 11/30
Answer:
28 is the GCF
Step-by-step explanation:
What I know about GCF is that it's a greatest (G) common (C) factor (F). The GCF of 84 and 56 is 7142128; false.
56- 56, 28, 14, 8, 7, 4, 2, 1.
84- 84, 42, 28, 21, 14, 12, 7, 6, 4, 3, 2, 1.
Hope this helps. :)
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
