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yuradex [85]
3 years ago
9

How can the effect of an outlier be overcome in an experiment that examines a random sample of a population?

Mathematics
1 answer:
Step2247 [10]3 years ago
3 0
To overcome and identify outliers, the data obtained can be arranged into from the highest to lowest and be oberved on which values have the highest or lowest value. 

Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
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The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?
Serhud [2]

Answer:

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

Step-by-step explanation:

Given - The circumference of the ellipse approximated by C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }where 2a and 2b are the lengths of 2 the axes of the ellipse.

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Solution -

C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi }  =  \sqrt{\frac{a^{2} + b^{2} }{2} }

Squaring Both sides, we get

[\frac{C}{2\pi }]^{2}   =  [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2}  }   =  {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2}  }   =  {{a^{2} + b^{2} }

\frac{C^{2} }{2(\pi )^{2} }  = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} }  -  a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}  = b

∴ we get

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

8 0
3 years ago
Find the angle of elevation of a kite on a 50m<br> string flying 40m vertically above the ground.
Lera25 [3.4K]
Sin(x)=40/50
x= sin^-1(40/50)
x= 53.1301023542—>53.1 rounded to the nearest tenth
angle of elevation is 53.1
6 0
3 years ago
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