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3 years ago

How can the effect of an outlier be overcome in an experiment that examines a random sample of a population?

1 answer:

3 0

To overcome and identify outliers, the data obtained can be arranged into from the highest to lowest and be oberved on which values have the highest or lowest value.

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Joe has 12 cups of soup in a pot. If he puts 1/4 cup of soup into each bowl, how many bowls will be used?

givi [52]

Answer:

Step-by-step explanation:

you need 4 one-fourth cups to make one cup. multiply 12 by 4 and you get 48

5 0

3 years ago

How long would it take you to double your money is the bank pays 3.6% interest, compounded

Lapatulllka [165]

Answer:

$t=19.25\ years$

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\P=x\\r=3.6\%=3.6/100=0.036\\A=2x$

substitute in the formula above

$2x=x(e)^{0.036t}$

solve for t

simplify

$2=(e)^{0.036t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.036t}]$

Applying property of exponents

$ln(2)=[0.036t]ln(e)$

Remember that ln(e) =1

$ln(2)=[0.036t]$

$t=ln(2)/[0.036]$

$t=19.25\ years$

7 0

3 years ago

(-1)3 exponet is 3 help me please i dont want to fail

Natali5045456 [20]

Answer:

-1

i do not remember how to solve this but i just answered a question that had this problem in it on my algebra test and that is the right answer

8 0

3 years ago

Question 2<br> Write an algebraic expression for the verbal expression.<br> a number n less 35

Contact [7]

X < 35
Hope this helps

6 0

3 years ago

Read 2 more answers

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

8 0

3 years ago