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3 years ago

Help please!!!!!!!!!!!!!!

Mathematics

1 answer:

Lapatulllka [165]3 years ago

5 0

Answer:

3(n + 2) > 0

Step-by-step explanation:

Work on a piece at a time.

"sum of a number and two": n + 2

"three times the sum of a number and two": 3(n + 2)

"three times the sum of a number and two is greater than zero": 3(n + 2) > 0

Answer: 3(n + 2) > 0

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Simplify: |3 – 8| - (12 divided by 3 + 1) to the power of 2

Harlamova29_29 [7]

Answer:

-4

Step-by-step explanation:

Assuming that the following equation is correct, begin by solving the operations within parentheses and absolute value expressions.

|3 - 8| - $(\frac{12}{3+1} )^2$

|-5| - $(\frac{12}{4} )^2$

The absolute value of -5 is 5; -5 is five units away from 0. 12/4 is equal to 3.

5 - $3^2$

5 - 9 = -4

The simplified expression is equal to -4.

4 0

3 years ago

Read 2 more answers

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

3 years ago

A company ordered paper supplies. They bought five times white

Law Incorporation [45]

Answer:

they ordered 10 sheets of green paper

Step-by-step explanation:

they would have to be equal since there was five times white as green and green cost five cents

given this you would split it 50 50

50 divided by 5 is 10 and 50 divided by 1 is 50

hope this helps and if it is right could I please have a brainliest?

7 0

3 years ago

The circumference of a circular hot tub at a hotel is 56.5 yards. What is the diameter of the hot tub?

Scorpion4ik [409]

$c = 2\pi \times r \\ 56.5 \div 2 = \pi \times r \\ 28.25 \div \pi = r \\ 9 = r \: then \: \times 2 = d \: \\ diameter \: is \: 18$

7 0

3 years ago

The sum of 15 and the product of 5 and v

pogonyaev

The answer is 3 because 3×5=15

7 0

3 years ago