How many distinct products can be formed using two different integers from the given set: {–6, –5, –4, –3, –2, –1, 0, 1, 2, 3, 4
zhannawk [14.2K]
Number of distinct products that can be formed is 144
<h3>Permutation</h3>
Since we need to multiply two different integers to be selected from the set which contains a total of 12 integers. This is a permutation problem since we require distinct integers.
Now, for the first integer to be selected for the product, since we have 12 integers, it is to be arranged in 1 way. So, the permutation is ¹²P₁ = 12
For the second integer, we also have 12 integers to choose from to be arranged in 1 way. So, the permutation is ¹²P₁ = 12.
<h3>
Number of distinct products</h3>
So, the number of distinct products that can be formed from these two integers are ¹²P₁ × ¹²P₁ = 12 × 12 = 144
So, the number of distinct products that can be formed is 144
Learn more about permutation here:
brainly.com/question/25925367
Answer:
A.
Step-by-step explanation:
Answer:
(2x-5)(3x-2)
Step-by-step explanation:
1)When factoring quadratic equations in for ax²+bx+c you need to separate the b term in a way that the two addends you separate it by should equal a•c. Just do trial and error. In this case you should get -4 and -15. Your separated equation should be:
6x²-4x-15x+10
2)now factor out a common factor from the first two terms and one from the last two terms you should have:
2x(3x-2)-5(3x-2)
3)finally rewrite this equation into two separate factors and you have your answer.
Answer:
1/150000
Step-by-step explanation:
from km to cm you should multiply it by 100000
Answer: unknown
Step-by-step explanation: what 3 options please link a picture or finish the question so i may help
