Answer:
No.
Step-by-step explanation:
It is not because 20 is not a perfect square.
Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
Please give me Brainliest
Answer:A fine of $0.75 is paid if the book returned by the due date.
No fine is paid if the book is returned 1 day after the due date.
A fine of $0.75 is paid if the book is returned 1 day after the due date.
Bit by bit clarification:
A fine of $0.75 is paid if the book returned by the due date.
No fine is paid if the book is returned 1 day after the due date.
A fine of $0.75 is paid if the book is returned 1 day after the due date.
I think it is coefficient, hope this helps!
A. (2,0) (0,-3)
B. slope= 3/2
C. y= 3/2x-3
D. 3/2x+y= -3
