So we know that the equation for density is:
![D=\frac{m}{V}](https://tex.z-dn.net/?f=%20D%3D%5Cfrac%7Bm%7D%7BV%7D%20)
where D is the density, m is the mass in grams, and V is the volume in mL.
So since we know two of the variables, mass and density, we can solve for the volume:
![\frac{1.020g}{mL}=\frac{147g}{V}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1.020g%7D%7BmL%7D%3D%5Cfrac%7B147g%7D%7BV%7D%20)
![V=\frac{147g}{\frac{1.020g}{mL}}](https://tex.z-dn.net/?f=%20V%3D%5Cfrac%7B147g%7D%7B%5Cfrac%7B1.020g%7D%7BmL%7D%7D%20)
![V=144.12mL](https://tex.z-dn.net/?f=%20V%3D144.12mL%20)
Therefore, the volume of this urine sample is 144.12mL.
Answer:
1.57 x 10⁷m
Explanation:
Given quantity is;
1.57 x 10¹⁴nm
Now;
1 nm = 10⁻⁹
So, let us convert this given quantity;
1 nm = 10⁻⁹
1.57 x 10¹⁴nm will give 1.57 x 10¹⁴ x 10⁻⁹ = 1.57 x 10⁷m
Answer:
The mass percentage of nitrogen in the sample is 1.96%.
Explanation:
21.0 mL of 0.150 M HCl
Moles of hydrogen chloride = n
Volume of hydrogen chloride solution = 21.0 mL = 0.021 L
Molarity of the hydrogen chloride = 0.150 M
![n=0.150 M\times 0.021 L=0.00315 mol](https://tex.z-dn.net/?f=n%3D0.150%20M%5Ctimes%200.021%20L%3D0.00315%20mol)
![NH_3 (aq) + HCl(aq)\rightarrow NH_4Cl ( aq )](https://tex.z-dn.net/?f=NH_3%20%28aq%29%20%2B%20HCl%28aq%29%5Crightarrow%20NH_4Cl%20%28%20aq%20%29)
According to recation, 1 mole of HCl neutralizes 1 mole ammonia.Then 0.00315 moles of HCl will neutrtalize:
of ammonia
1 mole of ammonia has 1 mole of nitrogen atom . Then 0.00315 moles of ammonia will have = 1 × 0.00315 mol = 0.00135 mol
Mass of 0.00315 moles of nitrogen= 0.00315 mol × 14 g/mol = 0.0441 g
Mass of the sample = 2.25 g
The mass percentage of nitrogen in the sample:
![\%=\frac{0.0441 g}{2.25 g}\times 100=1.96\%](https://tex.z-dn.net/?f=%5C%25%3D%5Cfrac%7B0.0441%20g%7D%7B2.25%20g%7D%5Ctimes%20100%3D1.96%5C%25)
The planets that could host liquid water and might have rocky ... Liquid water is a necessity for the kind of life we know