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Sveta_85 [38]
2 years ago
12

Which of the following statements about gases is false?

Chemistry
1 answer:
erma4kov [3.2K]2 years ago
3 0

Answer:

  • <u><em>It is false that all gases are colorless and odorless at room temperature (option C below)</em></u>

Explanation:

The answer choices are:

  • A) Gases expand spontaneously to fill the container they are placed in.
  • B) Non-reacting gas mixtures are homogeneous
  • C) All gases are colorless and odorless at room temperatune
  • D) Distances between molecules of gas are very large compared to bond distances within molecules
  • E) Gases are highly compressible.

<h2>Solution</h2>

Let's review each statement

<u><em>A) Gases expand spontaneously to fill the container they are placed in. </em></u>

This is correct. On of the properties of gases is that the particles (atoms or molecules) are not attracted to each other and can move freely. The gas substances do not have definite volume, but occupy all the space available, taking the form and volume of the container.

<u><em>B) Non-reacting gas mixtures are homogeneous </em></u>

This is correct. Since in a mixture of gases, every gas moves freely inside the container, the particles of all gases are intimately mixed without being able to physically distinguish one gas from another, which constitutes a homogeneous mixture.

<u><em>C) All gases are colorless and odorless at room temperatune.</em></u>

This is false. Some gases have color, some have odor, and some have both color and odor.

Some chemical reactions are evidenced when a color gas or a straneous olor evolves from the reaction.

For instance, the gases that evolve when food is rotten have a very unpleasant olor.

<u><em>D) Distances between molecules of gas are very large compared to bond distances within molecules</em></u>

This is correct. This is one of the assumptions of the molecular kinetic theory of gases that leads to the fact that gas molecules do not interact with each other and that the space occupied by the molecules themselves is negligible.

<u><em></em></u>

<u><em>E) Gases are highly compressible. </em></u>

This is correct. Since the gas particles are widely separated, most of the space in a gas is empty. Therefore, increasing the pressure, the empty space will decrease and the gas will occupy less volume. This is what compressible means: the volume can be reduced by applying pressure.

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Polonium- 210 , Po210 , decays to lead- 206 , Pb206 , by alpha emission according to the equation Po84210⟶Pb82206+He24 If the ha
elixir [45]

Answer:

0.269 g

Explanation:

Po_{210} ^{84}  ⟶  Pb_{206} ^{82}+  + He_{4} ^{2}

Data:

Half-life of  Po_{210} ^{84}  (T(1/2)) = 138.4 days

Mass of PoCl4 = 561 mg (0,561 g) and molecular weight of PoCl4 = 350. 79 g/mol  

Time = 338.8 days  

Isotopic masses  

Po_{210} ^{84} = 209.98 g/mol  

Pb_{206} ^{82} = 205.97 g/mol  

Concepts  

Avogadro’s number: This is the number of constituent particles that are contained in a mol of any substance. These constituted particles can be atoms, molecules or ions). Its value is 6.023*10^23.  

The radioactive decay law is  

N=Noe^(-λt)

Where:  

No = number of atoms in t=0

N = number of atoms in t=t (now) in this case t=338.8 days  

λ= radioactive decay constant  

The radioactive constant is related to the half-life by the next equation  

λ= \frac{ln 2}{t(1/2)}

so  

λ= \frac{ln2}{138.4 days}  =0,005008 days^(-1)

No (Atoms of  Po_{210} ^{84}  in t=0)

To get No we need to calculate the number of atoms of  Po_{210} ^{84}   in the initial sample. We have a sample of 0,561 g of PoCl4. If we get the number of moles of PoCl4 in the sample, this will be the number of moles of  Po_{210} ^{84}  in the initial sample.  

This is:

\frac{0,561 g of PoCl4}{350. 79 g of PoCl4 /mol} = 0,001599 mol of  PoCl4

This is the number of mol of  Po_{210} ^{84} in the initial sample.

To get the number of atoms in the initial sample we use the Avogadro’s number = 6.023*10^23  

0,001599 mol of  Po_{210} ^{84} * 6.023*10^23 atoms/ mol of  Po_{210} ^{84} = 9.632 *10^20 atoms of  Po_{210} ^{84}

Atoms after 338.8 days

We use the radioactive decay law to get this value  

N=Noe^(-λt)

N=9.632*10^20 e^(-0,005008 days^(-1) * 338.8 days) =1.765*10^20

This is the number of atoms of  Po_{210} ^{84} in the sample after 338.8 days has passed  

The number of atoms  Po_{210} ^{84} transformed is equal to the number of atoms of Pb_{206} ^{82}  produced.  

The number of atoms of Po_{210} ^{84} transformed is No - N  

9.632 *10^20 – 1.765 *10^20 = 7.866*10^20

So, 7.866*10^20 is the number of atoms of Pb_{206} ^{82} produced  

We can get the mass with the Avogadro’s number

(7.866*10^20 atoms of Pb_{206} ^{82} ) / ( 6.023*10^23 atoms of Pb_{206} ^{82} / mol of Pb_{206} ^{82} =  0.001306 moles of Pb_{206} ^{82}

This number of moles have a mass of:

(0,001306 moles of Pb_{206} ^{82} )* (205.97 g of Pb_{206} ^{82} /mol of Pb_{206} ^{82} ) = 0.269 g  

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3 years ago
Good day pleases help
klemol [59]
I can’t see the choices can you take another picture of this assignment please so i can help you
6 0
2 years ago
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