How many half lives would pass if a mass of copper-66 decayed for 51 minutes? The half life of Cu-66 is 5.10 minutes.

Please helpppppppppp

IgorC [24]

Answer:

Plants take carbon dioxide from the air and use it to make food.

Explanation:

4 0

2 years ago

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Calculate the relative rate of effusion for the orange to blue spheres. The root-mean-square speed for the orange spheres is 565

Tanzania [10]

Answer:

Relative rate of effusion for the orange to blue spheres = 1.531

Explanation:

Rate of effusion of Orange / Rate of effusion of blue = [Mblue / Morange]^1/2

Vrms = sqrt [(3RT/M)]

Vorange / Vblue = [ Mblue / Morange]^1/2

Rate of effusion of Orange / Rate of effusion of blue = 565/ 369 = 1.531

5 0

3 years ago

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An unknown organic compound composed of carbon, hydrogen, and oxygen was analyzed and found to be 50.84% C, 8.53% H, and the res

MariettaO [177]

In every 100g of that compund there is 50.84 g of C, 8.53 g H and (100-59.37) g = 40.63 g of O.

Step 1: Convert each element's mass in moles. To do that we need to divide each element's mass by their respective molar mass.

For Carbon.

$C = \frac{50.84}{12} = 4.24 mol$

For Hydrogen.

$H = \frac{8.53}{1} = 8.53 mol$

For Oxygen.

$O = \frac{40.63}{16} = 2.54 mol$

Step 2: Divide each of the numbers by the smallest number.

For Carbon.

$C = \frac{4.24}{2.54} = 1.7$

For Hydrogen.

$H = \frac{8.53}{2.54} = 3.36$

For Oxygen.

$O = \frac{2.54}{2.54} = 1$

Step 3: So the empirical formula will be.

$C_{1.7} H_{3.36} O_1$

But using decimal will be messy. So we multiply the numbers by 3. The right empirical formula will be.

$C_{5} H_{10} O_3$

7 0

2 years ago

Solid mixture contains MgCl2 and NaCl. When 0.5000 g of this solid is dissolved in enough water to form 1.000 L of solution, the

aksik [14]

Answer:

83,40 (w/w) %

Explanation:

The osmotic pressure (π) is defined as:

π = iMRT

Where i is Van't Hoff factor (3 for MgCl₂ and 2 for NaCl), M is molarity, R is gas contant (0,082atmL/molK) and T is temperature (298,15K)

iM = π / RT

iM = 0,01607mol/L

It is possible to write:

3x+2y = 0,01607mol/L (1)

Where x are moles of MgCl₂ and y moles of NaCl.

-M = moles of each compund because M is molarity (moles/L) and there is 1,000L-

Knowing molar mass of MgCl₂ is 95,2 g/mol and for NaCl is 58,44g/mol:

x×95,211 + y×58,44 = 0,5000g (2)

Replacing (2) in (1):

3x+2(0,0086 - 1,629x) = 0,01607mol/L

-0,258x = -0,00113

x = 0,004380 moles of MgCl₂

In grams:

0,004380 moles of MgCl₂×(95,211g/mol) = 0,417g of MgCl₂

Mass percent is:

(0,4170g of MgCl₂/0,5000g of solid) ×100 = 83,40 (w/w) %

I hope it helps!

4 0

2 years ago

Is gunpowder a homogenous mixture or a heterogenous mixture? Explain why.

inysia [295]

Gunpowder is a heterogenous mixture,

Reason : the composiotion of the mixture is not uniform throughout, the mixture can be separated by a suitable method , and finally , it composes of charcoal, sulfur and potassium nitrate which is not homogeneous mixture.

4 0

1 year ago