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Tatiana [17]
4 years ago
7

Ionic compounds are normally in which physical state at room temperature?

Chemistry
2 answers:
Ivahew [28]4 years ago
8 0
<span>Ionic compounds are normally in which physical state at room temperature in solid. The answer is A. 

</span>Ionic Compounds Are Balanced. Table salt is an example of an ionic compound. Sodium<span> and </span>chlorine<span>ions come together to form </span>sodium chloride<span>, or </span>NaCl<span>. The </span>sodium atom<span> in this compound loses an electron to become Na+, while the </span>chlorine<span> atom gains an electron to become Cl-.</span>
Viktor [21]4 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

Ionic compounds have atoms bonded through ionic bonds.

An ionic bond is formed when there is transfer of electrons from one atom to another. Also, ionic compounds have opposite charge on their atoms hence, they are attracted by strong intermolecular forces.

Thus, compound whose atoms are holded by strong intermolecular forces of attraction are solid.

Therefore, we can conclude that ionic compounds are normally in solid physical state at room temperature.

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Combustion of hydrocarbons such as undecane (C_11H_24) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Eart
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Answer:

Volume of carbon dioxide is 428.23 L.

Explanation:

Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion)  and produces carbon dioxide and water as a product in the gaseous form.

The molar mass of undecane = 156.31 g/mol.

\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.

Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.

V = \frac{nRT}{P} \\

V = \frac{18.26 \times 0.082 \times 286 \ K}{1atm} \\

V = 428.23 \ L

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