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Tatiana [17]
4 years ago
7

Ionic compounds are normally in which physical state at room temperature?

Chemistry
2 answers:
Ivahew [28]4 years ago
8 0
<span>Ionic compounds are normally in which physical state at room temperature in solid. The answer is A. 

</span>Ionic Compounds Are Balanced. Table salt is an example of an ionic compound. Sodium<span> and </span>chlorine<span>ions come together to form </span>sodium chloride<span>, or </span>NaCl<span>. The </span>sodium atom<span> in this compound loses an electron to become Na+, while the </span>chlorine<span> atom gains an electron to become Cl-.</span>
Viktor [21]4 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

Ionic compounds have atoms bonded through ionic bonds.

An ionic bond is formed when there is transfer of electrons from one atom to another. Also, ionic compounds have opposite charge on their atoms hence, they are attracted by strong intermolecular forces.

Thus, compound whose atoms are holded by strong intermolecular forces of attraction are solid.

Therefore, we can conclude that ionic compounds are normally in solid physical state at room temperature.

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Be sure to answer all parts. In the electrolysis of molten BaI2, (a) What product forms at the negative electrode? (b) What prod
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Answer:

(a) Barium is produced at the negative electrode

(b) Iodine is produced at the positive electrode

Explanation:

When  an electric current is passed through a solution containing electrolyte, a non spontaneous reaction is stimulated. This results in the flow of <u>positively charged ions to negatively charged electrodes(</u><u>cathode</u><u>) and negatively charged ions to positively charged electrodes(</u><u>anode</u><u>)</u>

When an electric current is passed through molten BaI_{2} in the electrolytic cell, the following reactions takes place:

                                            BaI_{2} → Ba^{2+} + 2I^{-}

At the anode;

Iodine ions will lose an electron and will be oxidized to iodine

2I^{-} → I_{2} + e^{-}

At  the cathode;

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Ba^{2+} + 2e^{-} → Ba

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A 280 mL bubble contains 0.283 g of a gas at 0.951 atm and 25.0°C What is the molar mass of this gas?
tekilochka [14]

Answer: 28.3 g/mol

Explanation:

According to the ideal gas equation:'

PV=nRT

P= Pressure of the gas = 0.951 atm

V= Volume of the gas = 280 mL = 0.28 L     (1L=1000 ml)

T= Temperature of the gas = 25°C=(25+273)K=298 K   (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm/K mol

n=\frac{PV}{RT}=\frac{0.951\times 0.28L}{0.0821 \times 298}=0.010moles

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

0.010=\frac{0.283}{\text {Molar mass}}

{\text {Molar mass}}=28.3g/mol

Thus the molar mass of the gas is 28.3 g/mol.

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