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vagabundo [1.1K]
3 years ago
9

Pls helpp! help me with this maths question 10 points available pls thank you

Mathematics
2 answers:
hammer [34]3 years ago
6 0

Answer:

53.9

Step-by-step explanation:

you add all of the sides up

damaskus [11]3 years ago
4 0

Answer:

178.07

Step-by-step explanation:

First you have to multiply 13 x 16 = 208. After that you have to find the area of the missing piece, to find that you have to add 5.7 + 6.2 = 11.9, and then subtract by 16 to get 4.1. Then you multiply 7.3 x 4.1 = 29.93.

29.93 is the area of the missing piece

So you would subtract the area of the whole thing (208) by the area of the piece (29.93)

To get the answer 178.07

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Use the present value formula to determine the amount to be invested now, or the present value needed.
Vladimir79 [104]

Answer:

The value needed now is $102,296.60

Step-by-step explanation:

Here, we want to calculate the present value needed.

We shall be using the formula for compound interest here

Mathematically;

A = I(1 + r/n)^nt

According to the question;

I is the initial amount which is what we want to calculate

A is the accumulated amount with interest = 140,000

r is the interest rate = 8% = 8/100 = 0.08

n is the number of times interest is compounded which is 4, since it is quarterly

t is the number of years = 2

Substituting these values, we have ;

140,000 = I(1 + 0.08/2)^(4 * 2)

140,000 = I(1.04)^8

I = 140,000/(1.04)^8

I = 102,296.62870027774

Which is I = $102,296.60 to the nearest cent

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3 years ago
What is the equation of the following graph?
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5 0
3 years ago
Alma is estimating the proportion of students in her school district who, in the past month, read at least 1 book. From a random
Maurinko [17]

Answer:

D)

(0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the random sample size 'n' = 50

The sample proportion

                       p^{-} = \frac{32}{50} = 0.64

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(p^{-} - Z_{0.90} \sqrt{\frac{p(1-p)}{n},  } , p^{-} +Z_{0.90} \sqrt{\frac{p(1-p)}{n} })

<u><em>Step(ii):-</em></u>

Level of significance = 0.90

Z₀.₉₀ = 1.645

(0.64 - 1.645 \sqrt{\frac{0.64(1-0.64)}{50},  } , 0.64 +1.645 \sqrt{\frac{0.64(1-0.64)}{50} })

(0.64 - 1.645 \sqrt{\frac{0.64(0.36)}{50},  } , 0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })

(0.64 -1.645(0.06788) , (0.64 + 1.645(0.06788)

(0.52846 , 0.75166)

<u><em>Final answer:-</em></u>

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

5 0
3 years ago
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