Answer:
The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Step-by-step explanation:
Given information:
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.


We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

According to Pythagoras


.... (1)
Put z=1 and y=2, to find the value of x.




Taking square root both sides.

Differentiate equation (1) with respect to t.

Divide both sides by 2.

Put
, y=2,
in the above equation.

Divide both sides by 2.



Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Answer: 13,000
Step-by-step explanation:
I = prt
I = (.65)($4000)(5)
I = 2600(5)
I = 13,000
The correct answer is: "
" .
____________________
<u>Step-by-step explanation</u>:
Based on the assumption that the "1" repeats infinitely; in the given value:
" 33.61111111 ...." ;
_______
Note that the "611" ; after the decimal point; this goes to the "thousandths";
place (is "3 (three) digits long.").
_______
As such; we rewrite the number as:
_______
"
" ;
and we multiply BOTH the "numerator" And the "denominator" by: "1000" :
_______
→ "
" ;
to get:
→ "
" ; → which cannot be reduced any further.
_______
The correct answer is: "
" .
_______
Hope this is helpful to you!
Wishing you the best!
_______
5x + 60y = 35
x +y = 1.5 : rewrite as x = 1.5-y and substitute this formula for x in the first one:
5(1.5-y) + 60y = 35
distribute:
7.5 - 5y + 60y = 35
combine like terms:
7.5 + 55y = 35
subtract 7.5 from both sides:
55y = 27.5
divide both sides by 55 to solve for y
y = 27.5 / 55 = 0.5
now substiute 0.5 for y in the 2nd equation:
x + 0.5 = 1.5
x = 1.5 - 0.5 = 1
he walked for 1 hour