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nataly862011 [7]
2 years ago
7

A pilot is allowed to fly a maximum of 60,000 minutes per year How many hours is a pilot allowed to fly in a year? (Round to the

nearest whole hour, if necessary.)​
Mathematics
1 answer:
enot [183]2 years ago
8 0
The answer is 1000 hours
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A label is placed around the juice box below, not including the bases. Determine the surface area of the label.
il63 [147K]

Answer:

7.5in explanation:4in+2in+1.5in=7.5in

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Toyota is discounting all their 2020 cars by 21% to make room for the new 2021 vehicles. A 2020 Rav 4 has a sticker price of $23
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B $18,861.25

Step-by-step explanation:

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2 years ago
A robotic machine fills containers with an acid solution at the rate of 50 + 5 t milliliters (mL) per second, where t is in seco
Alika [10]

Answer:

12,000

Step-by-step explanation:

The machine fills the containers at a rate of 50+5t milliliters (mL) per second.

Therefore, the rate of change of the number of containers, N is:

\dfrac{dN}{dt}=50+5t, 0\leq t\leq 60

dN=(50+5t)dt\\$Taking integrals of both sides\\\int dN=\int (50+5t)dt\\N(t)=50t+\frac{5t^2}{2}+C $(C a constant of integration)\\\\When t=0, , No containers are filled, therefore:$ N(t)=0\\0=50(0)+\frac{5(0)^2}{2}+C\\C=0\\$Therefore, N(t)=50t+2.5t^2

When t=60 seconds

N(60)=50(60)+2.5(60)^2\\N(60)=12000$ mL

Therefore, 12,000 milliliters of acid solution are put into a container in 60 seconds.

7 0
2 years ago
A parabola can be drawn given a focus of
Volgvan

Answer:

y=-\frac{1}{4}(x-2)^{2}+9

Step-by-step explanation:

Any point on a given parabola is equidistant from focus and directrix.

Given:

Focus of the parabola is at (2,8).

Directrix of the parabola is y=10.

Let (x,y) be any point on the parabola. Then, from the definition of a parabola,

Distance of (x,y) from focus = Distance of (x,y) from directrix.

Therefore,

\sqrt{(x-2)^{2}+(y-8)^{2}}=|y-10|

Squaring both sides, we get

(x-2)^{2}+(y-8)^{2}=(y-10)^{2}\\(x-2)^{2}=(y-10)^{2}-(y-8)^{2}\\(x-2)^{2}=(y-10+y-8)(y-10-(y-8))...............[\because a^{2}-b^{2}=(a+b)(a-b)]\\(x-2)^{2}=(2y-18)(y-10-y+8)\\(x-2)^{2}=2(y-9)(-2)\\(x-2)^{2}=-4(y-9)\\y-9=-\frac{1}{4}(x-2)^{2}\\y=-\frac{1}{4}(x-2)^{2}+9

Hence, the equation of the parabola is y=-\frac{1}{4}(x-2)^{2}+9.

4 0
3 years ago
Find the perimeter and area of the figure.
Jobisdone [24]
The area is 36 and the perimeter is 26
5 0
3 years ago
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