Answer:
(A) t_H = Vo×Sin (theta)/g
(B) t,_R = (2VoSin(theta))/g
(C) H = Vo²Sin²(theta) / 2g
(D) Range = Vo²Sin(2×theta) / g.
Explanation:
The detailed solution to the problem can be found in the attachment below
Answer:
(a) The angle of projection is 63 degree.
(b) The velocity of projection is 24.5 m/s.
Explanation:
Height, h = 1 m
horizontal distance, d = 50 m
time, t = 4.5 s
Let the initial velocity is u and the angle is A.
(a) Horizontal distance = horizontal velocity x time
50 = u cos A x 4.5
u cos A = 11.1 .....(1)
Use second equation of motion in vertical direction
Divide (2) by (1)
tan A = 1.97
A = 63 degree
(b) Substitute the value of A in equation (2)
u x sin 63 = 21.8
u = 24.5 m/s
The sum of angles in a regular pentagon is
180*(5 - 2) = 540°
Each internal angle is 540/5 = 108°.
Each vertex creates a line of symmetry to the midpoint of the opposite side,
as shown in the figure.
Answer: 5 lines of symmetry.