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makvit [3.9K]
3 years ago
7

Can u help me thanks so Much ❤️

Physics
1 answer:
Nuetrik [128]3 years ago
3 0
1) Constant speed
2) Slowing down
3) Not moving
4) Speeding up
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A. Analog signal

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3 years ago
A ball is thrown so that its initial vertical and horizontal components of velocity are 30 m/s and 15 m/s, respectively. Estimat
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Answer:

H = 45 m

Explanation:

First we find the launch velocity of the ball by using the following formula:

v₀ = √(v₀ₓ² + v₀y²)

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v₀y = Vertical Component of Launch Velocity = 30 m/s

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v₀ = √[(15 m/s)² + (30 m/s)²]

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Now, we find the launch angle of the ball by using the following formula:

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θ = tan⁻¹ (2)

θ = 63.43°

Now, the maximum height attained by the ball is given by the formula:

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<u>H = 45 m</u>

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We are given with the expression d = ut + 0.5 at^2 and is asked to express the equation in terms of a. First, we transpose ut to the left side, then we multiply to the equation and divide lastly the resulting equation by t^2. The final expression becomes a = 2(d-ut)/t^2.
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