<h2>Answer:</h2>
The offspring population will contains the desirable characteristics of both fantail pigeon and the fantail pigeon.
<h3>Explanation:</h3>
- The selective breeding is the planned breeding between two organism of the population with desirable properties to result in the new traits from both parents in the single next generation offspring.
- In this case, the offspring of the pouter pigeon and the fantail pigeon will contain the traits of pouter and it also has fantail.
- The new generation will be selective breed an it is from the breeding of intra specie organism. If breeding is inter specie than the offspring is most probably infertile.
oogonia no result of oogonia human
ovogonia:Esto quiere decir que la ovogonia tenía 46 cromosomas como se afirmó anteriormente, y el ovocito debe sufrir una reducción por medio de la denominada Meiosis hasta tener 23 cromosomas, 22 cromosomas somáticos y un cromosoma X (22X), el cual es el número Haploide
I hope it helps you.
YES THAT FIRST SENTENCE IS VERY TRUE.YES, GENE DOPING IS USED BY MANY ATHLETES AROUND THE WORLD.IT CAUSES SEVERAL EFFECTS LIKE:
a) increased extraordinary hematocrit
b) increased thrombotic activity
c) autoimmune anemia,ETC.
ANY TWO GENETIC MODIFICATIONS THAT WOULD IMPROVE THE PERFORMANCE OF AN ATHLETE ARE:
a.gene therapy should be given to produce more hormones in the body.
b. gene therapy is given to athletes because they have been used to study and model cancer (the oncomouse), obesity, heart disease, diabetes, arthritis, substance abuse, anxiety, aging and Parkinson disease to check for the athletes.
Answer:
25%
Explanation:
When looking at a pedigree remember that:
- squares are males
- circles are females
- the solid colored figure represents an individual affected by a disease
- the empty figure represents a healthy individual
Let us assign the symbol X⁺ to represent the dominant allele linked to the X-chromosome and expressing healthiness, and X⁻ to represent the recessive allele expressing the dissease.
According to this pedigree
- I1 is a man affected by the disease, YX⁻
- I2 is a healthy woman X⁺X⁻
- we can see that among the progeny (generation II) there are two individuals affected (a boy and a girl) and one healthy girl. This means that the mother I2 is heterozygous for the trait.
So, having their genotypes we can know what are the probabilities of getting a son with DMD
Parentals) YX⁻ x X⁺X⁻
Gametes) Y X⁻ X⁺ X⁻
Punnett square)
X⁺ X⁻
X⁻ X⁺X⁻ X⁻X⁻
Y X⁺Y X⁻Y
F1)
- The probabilities of getting a healthy daughter X⁺X⁻ are 25%
- The probabilities of getting a healthy son X⁺Y are 25%
- The probabilities of getting a daughter with DMD X⁻X⁻ are 25%
- The probabilities of getting a son with DMD X⁻Y are 25%
