Let’s assume a wire-hair terrier is a true breed for wire hair with alleles (BB) and a smooth-hair terrier is true breed for smooth hair (bb). Allele B is dominant over its allele b. When these two terrier mated and produce offspring wire-hair terrier and smooth-hair terrier in the ratio 3:1.
Based on this result it can be inferred that –
a. The pattern of inheritance is monohybrid cross.
b.Genotype of wire-hair terrier (1BB and 2 Bb) and genotype of smooth-hair terrier is (bb)
c. Phenotype ratio will be 3:1 and genotypic ratio will be 1:2:1.
Answer:
i have no clue, but nobody likes the virus.
Answer:
There is no answer to that.
Explanation:
- Chlorophyll is located in the chloroplast, and it is a crucial component in green plants for photosynthesis.
- Cells walls are present in plant cells only.
- Large central vacuoles are part of plant cells, too.
None of the options are correct.
In the absence of ADP, the conversion of NADH to NAD+ via the electron transport chain is prevented from happening.
<h3>What is glycolysis?</h3>
Glycolysis is the series of reactions by which glucose is broken down to pyruvate by the body.
NAD+ is a limiting factor in glycolysis. In the absence of ADP, the conversion of NADH to NAD+ via the electron transport chain is prevented from happening.
In conclusion, NAD+ is a limiting factor in glycolysis.
Learn more about glycolysis at: brainly.com/question/4355201
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Yes, living things break down polysaccharide into simple sugars.
