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lakkis [162]
3 years ago
9

A and b are positive integers. Find

gn="absmiddle" class="latex-formula"> if a^3b^2=72
Mathematics
1 answer:
lord [1]3 years ago
7 0

A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.

From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.

Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.

Divide everything by 8 to isolate b and you get that b^2=9.

Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.

Now that we know that a=2 and b=3 just plug them into the equation.

-2(2)+3(3)=?

-4+9=?

5

Sorry about having to use this ^ symbol, the equation maker is not working.

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  All proportions have <u>this</u> <u>form</u>:

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  Here we have two pairs of numbers:

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