3 years ago

How do you solve matrices

Mathematics

1 answer:

kiruha [24]3 years ago

3 0

I've included two pictures showing steps on how to solve. Hopefully this helps more than words.

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Which expression forms an equation with the given expression? 8•7-4=<br>

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3 years ago

The Average of 25, 29 and x is 29 Find x

arsen [322]

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33.

Step-by-step explanation:

( 25 + 29 + x) = 3*29 = 87

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3 years ago

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Find the absolute extrema of f(x) = e^{x^2+2x}f ( x ) = e x 2 + 2 x on the interval [-2,2][ − 2 , 2 ] first and then use the com

fredd [130]

$f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}$

$f$ has critical points where the derivative is 0:

$2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1$

The second derivative is

$f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}$

and $f''(-1)=\frac2e>0$ , which indicates a local minimum at $x=-1$ with a value of $f(-1)=\frac1e$ .

At the endpoints of [-2, 2], we have $f(-2)=1$ and $f(2)=e^8$ , so that $f$ has an absolute minimum of $\frac1e$ and an absolute maximum of $e^8$ on [-2, 2].

So we have

$\dfrac1e\le f(x)\le e^8$

$\implies\displaystyle\int_{-2}^2\frac{\mathrm dx}e\le\int_{-2}^2f(x)\,\mathrm dx\le\int_{-2}^2e^8\,\mathrm dx$

$\implies\boxed{\displaystyle\frac4e\le\int_{-2}^2f(x)\,\mathrm dx\le4e^8}$

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3 years ago

-4 = 8m please show step by step

GREYUIT [131]

so you do 8÷-4=2. so m equals 2

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3 years ago

Read 2 more answers