How many variable terms are in the expression 3x3y + 5x2 − 4y + z + 9?

Mathematics

1 answer:

Wittaler [7]3 years ago

5 0

Answer:

Step-by-step explanation:

"4" is the number of variable terms that are in the expression 3x3y + 5x2 _ 4y + z + 9. The four variable terms in the expression are "xy", "x^2", "y" and "z". I hope that this is the answer that you were looking for and the answer has actually come to your desired help. If you need any clarification, you can always ask.

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Mandy shaded the fraction strip below to represent a fraction Shade the fraction strip below so that it represents a fraction th

Aleksandr-060686 [28]

Your question is missing the figure, so the figure for your question is attached below:

Answer:

shade 2 strips out of 4 to get fraction strip equivalent to Mandy's fraction strip

Step-by-step explanation:

As Mandy shaded the 3 trips out of the total six strips. It shows the fraction of $\frac{3}{6}$

and $\frac{3}{6}=\frac{1}{2}$

To shade the given fraction strip so that it represents a fraction that is equivalent to Mandy's fraction strip, we should shade 2 stripes out of 4 that is equivalent to $\frac{1}{2}$

i.e. $\frac{2}{4}=\frac{1}{2}$

My Fraction Strip is equivalent to Mandy's Fraction Strip because both are equal to $\frac{1}{2}$

5 0

3 years ago

Write 3x^2-18x-6 in vertex form

Vedmedyk [2.9K]

The standard form of a quadratic equation is $\displaystyle{ y=ax^2+bx+c$ , while the vertex form is:

$y=a(x-h)^2+k$ , where (h, k) is the vertex of the parabola.

What we want is to write $\displaystyle{ y=3x^2-18x-6$ as $y=a(x-h)^2+k$

First, we note that all the three terms have a factor of 3, so we factorize it and write:

$\displaystyle{ y=3(x^2-6x-2)$ .

Second, we notice that $x^2-6x$ are the terms produced by $(x-3)^2=x^2-6x+9$ , without the 9. So we can write:

$x^2-6x=(x-3)^2-9$ , and substituting in $\displaystyle{ y=3(x^2-6x-2)$ we have:

$\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]$ .

Finally, distributing 3 over the two terms in the brackets we have:

$y=3[x-3]^2-33$ .

Answer: $y=3(x-3)^2-33$