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Vilka [71]
3 years ago
7

There are 5people trying for 3openings how many possible outcomes are there ​

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

60

Step-by-step explanation:

5×4×3 = 60

Alternately,

5C3 × 3! = 60

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Art [367]

7x-y-17=0

Step-by-step explanation:


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3 years ago
Find the value of the following expression:
Greeley [361]

Answer:

25

Step-by-step explanation:

Expression: <em>(2⁸ ⋅ 5⁻⁵ ⋅ 19⁰)⁻² ⋅ (5⁻²/2³)⁴ ⋅ 2²⁸</em>

Inner-most powers: 2⁻¹⁶ • 5¹⁰ • 1 • 5⁻⁸/2¹² • 2²⁸

Combine like terms: 2¹² • 5²/2¹²

Cancel out: 5²

Solve: 25

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3 years ago
If RS= 3x + 1 , ST= 2x -2 , RT= 64 , fine the value of x
Novay_Z [31]
The answer is 

RS=3 x 2 + 1, ST= 2 x 4 -2, RT= 64, i'm sorry if it didn't help
6 0
3 years ago
Find the unknown side length, x. Write your answer in simplest radical form.
Mama L [17]

<span>The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>

4 0
3 years ago
What is the value of the sum of all the terms of the geometric series 300, 60, 12, …?
ruslelena [56]
<h3>Answer:   375</h3>

=========================================

Work Shown:

a = 300 = first term

r = 60/300 = 0.2 = common ratio

We multiply each term by 0.2, aka 1/5, to get the next term.

Since -1 < r < 1 is true, we can use the infinite geometric sum formula below

S = a/(1-r)

S = 300/(1-0.2)

S = 300/0.8

S = 375

----------

As a sort of "check", we can add up partial sums like so

  • 300+60 = 360
  • 300+60+12 = 360+12 = 372
  • 300+60+12+2.4 = 372+2.4 = 374.4
  • 300+60+12+2.4+0.48 = 374.4+0.48 = 374.88

and so on. The idea is that each time we add on a new term, we should be getting closer and closer to 375. I put "check" in quotation marks because it's probably not the rigorous of checks possible. But it may give a good idea of what's going on.

----------

Side note: If the common ratio r was either r < -1 or r > 1, then the terms we add on would get larger and larger. This would mean we don't approach a single finite value with the infinite sum.

3 0
2 years ago
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