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MAVERICK [17]
3 years ago
10

What is the answer for 222,702 round to the nearest ten thousand

Mathematics
1 answer:
Dafna11 [192]3 years ago
5 0

222,702 rounded to the nearest ten thousand would be 220,000

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Miguel sells insurance. He earns a 6% commission on each sale he makes. Miguel has a goal of earning $600 in commissions. Miguel
WARRIOR [948]

Answer:

$564

Step-by-step explanation:

6% of 600 is 36

So 600-36= $564

7 0
3 years ago
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A doctor wants to estimate the mean HDL cholesterol of all​ 20- to​ 29-year-old females. The number of subjects needed to estima
Ludmilka [50]

Answer:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

ME represent the margin of error

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

2) Solution to the problem

Since the new Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Assuming that the deviation is known we can express the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =\pm 3 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

Replacing into formula (b) we got:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

8 0
3 years ago
I need help SOMEONE PLZ HELP ME OUT WITH THIS !! THANK UU
Mama L [17]

Answer:

since they are alternate exteriors, we put a equal sign

2x+78=5x+15

next we subtract 78 on both sides

2x+78-78=5x+15-78

2x=5x-63

then we subtract 5x on both sides

2x-5x=5x-5x-63

-3x=-63

after that we divide -3 on both sides

-3x/-3=-63/-3

and the answer is

x=21

Step-by-step explanation:

8 0
3 years ago
DOES ANYONE KNOW THIS
GREYUIT [131]

Answer: 13 players.


Step-by-step explanation:

1. Let's call:

 x: Price of the shirt (x=17)

 y: Price of socks  y=5.50

 n: number of players.

2. You know that the budget is $300 and you have the following formula given in the problem:

n(x+y)\leq300

3. Substitute values and solve for n.Then, you obtain the following result:

n(17+5.50)\leq300\\22.5n\leq300\\n\leq13.33

4. The answer is: 13 players.

5 0
3 years ago
Evaluate j/k -0.2k when j =25 and k = 5
denis-greek [22]
When you have an equation that has variables and you know the value of those variables, just plug it it. So plugging the vaules we get
\frac{25}{5}-\frac{1}{5}5
Just evaluating we get 4
5 0
3 years ago
Read 2 more answers
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