Answer:
D. The methyl group of acetyl CoA becomes radio-labeled
Explanation:
During the steps in glycolysis, the carbon at position 1, becomes C-1 in dihydroxyacetone phosphate during the cleavage of fructose-1,6-bisphosphate to dihydroxyacetone phosphate and glyceraldehyde-3-phosphate. Subsequently on isomerization of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate, C-1 of dihydroxyacetone phosphate becomes C-3 of glyceraldehyde-3-phosphate.
Furthermore, in pyruvate, the end product of glycolysis, C-3 is converted to a methyl group which then becomes the methyl group in the acetyl-CoA molecule produced from the oxidative decarboxylation of pyruvate.
Since the radioactive 14-C of radio-labeled glucose occupies position 1, it will become the methyl group of acetyl-CoA.
the answer is b............
The highlighted structure serves to prevent
anterior dislocation of the femur onto the tibia. This type of dislocation is
by far the communal type and typically results from external rotation, extension,
and forced abduction. It can be auxiliary divided based on where the humeral
head comes to lie, the division are as follows:
<span>1. </span>Subcoracoid: the most
common<span>
</span>
<span>2. Subglenoid
</span>
<span>3.Subclavicular
</span>
<span>4. Intrathoracic: the very
rare</span>
