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4 years ago

Find the median of 35,36,43,47,59,62,64,77,82,82,82,94,95,95,97

2 answers:

7 0

First you put them in order from least to greatest like you did than you count from each end and take of two at a time till you get to the middle number.

so your median is 77

9966 [12]4 years ago

3 0

It is 77 because it is in the middle

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Y+12=-50 ASAP help PLEASE!!

murzikaleks [220]

Y+12=-50 y=-62

To solve

Subtract 12 from each side of the equation

y=-62

Y=-62

4 0

4 years ago

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The table of values represents a function f(x).

TiliK225 [7]

Answer:

- The interval [9, 10] is 1,375% greater than the interval [5, 8].

- The interval [9, 10] is 14.75 times greater than the interval [5, 8].

Step-by-step explanation:

1. To solve this problem you must apply the following formula:

$AverageRateOfChange=\frac{y_{2}-y_{1}}{x_{2}-y_{1}}$

2. Let's calculate the average rate of change of each interval:

a) Interval [9,10]:

$=\frac{11,014-4,052}{10-9}=6,962$

b) Interval [5,8]:

$=\frac{1,491-75}{8-5}=472$

3. The difference is:

$6,962-472=6,490$

4. In percentage:

$(\frac{6,962-472}{472})(100)=1,375%$

5. You have that the interval [9,10] is 14.75 times greater than the interval [5,8], as you can see below:

$\frac{6,962}{472}=14.75$

3 0

4 years ago

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What is the slope of this graph??

aleksley [76]

The Slope will be -1

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3 years ago

Solve: 1. 1/6y− 1/2 =3− 1/2y 2. 4x+1/15 = 2x/10

kogti [31]

Answer:

First Equation → y = 21/4

Second Equation → x = -1/57

Explanation:

solving equation #1

step 1 - simplify

$\displaystyle\frac{1}{6}y - \displaystyle\frac{1}{2} = 3 - \displaystyle\frac{1}{2}y\\\\\displaystyle\frac{1}{6}* \displaystyle\frac{y}{1} - \displaystyle\frac{1}{2} = 3 - \displaystyle\frac{1}{2}* \displaystyle\frac{y}{1}\\\\\displaystyle\frac{y}{6} - \displaystyle\frac{1}{2} = 3 - \displaystyle\frac{y}{2}$

step 3 - multiply each side of the equation by six

$\displaystyle\frac{y}{6} - \displaystyle\frac{1}{2} = 3 - \displaystyle\frac{y}{2}\\\\\displaystyle\frac{y}{6} * \displaystyle\frac{6}{1}- \displaystyle\frac{1}{2} * \displaystyle\frac{6}{1}= \displaystyle\frac{3}{1} *\displaystyle\frac{6}{1} - \displaystyle\frac{y}{2}* \displaystyle\frac{6}{1}\\\\y - 3 = 18 - 3y$

step 4 - add three to both sides of the equation.

$y - 3 = 18 - 3y\\\\y-3+3=18+3-3y\\\\y = -3y+21$

step 5 - add three y to both sides of the equation.

$y = -3y+21\\\\y+3y = -3y+3y+21\\\\y+3y=21$

step 6 - simplify

$y+3y=21\\\\4y=21$

step 7 - divide both sides of the equation by four

$4y=21\\\\\displaystyle\frac{4y}{4} = \displaystyle\frac{21}{4}\\ \\y = \displaystyle\frac{21}{4}$

Therefore, the solution to the first given equation is y = 21/4 or y = 5.25.

solving equation #2

step 1 - simplify.

$4x + \displaystyle\frac{1}{15} = \displaystyle\frac{2x}{10} \\\\4x + \displaystyle\frac{1}{15} = 2*\displaystyle\frac{x}{10}\\\\4x+\displaystyle\frac{1}{15} = \displaystyle\frac{x}{5}$

step 2 - multiply each side of the equation by five.

$4x+\displaystyle\frac{1}{15} = \displaystyle\frac{x}{5}\\\\\displaystyle\frac{4x}{1}* \displaystyle\frac{5}{1} +\displaystyle\frac{1}{15} * \displaystyle\frac{5}{1} = \displaystyle\frac{x}{5}* \displaystyle\frac{5}{1} \\\\20x + \displaystyle\frac{1}{3} = x$

step 3 - subtract twenty x from each side of the equation.

$20x + \displaystyle\frac{1}{3} = x \\\\20x -20x+ \displaystyle\frac{1}{3} = x -20x\\\\\displaystyle\frac{1}{3} = -19x$

step 4 - divide each side of the equation by negative nineteen.

$\displaystyle\frac{1}{3} = -19x\\\\\displaystyle\frac{\displaystyle\frac{1}{3} }{-19} = \displaystyle\frac{-19x}{-19} \\\\-\displaystyle\frac{1}{57} = x$