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Allisa [31]
3 years ago
15

Find the coordinate for the mid point of the segment with the points given (-16,0)(0,-16)

Mathematics
1 answer:
lyudmila [28]3 years ago
6 0

Answer:

(-8,-8)

Step-by-step explanation:

Coordinates of a midpoint:

The coordinates of the midpoint of a segment is given by the mean of the coordinates of the endpoints.

In this question:

Endpoints (-16,0) and (0,-16).

x-coordinate:

\frac{-16+0}{2} = -8

y-coordinate:

\frac{0-16}{2} = -8

Then:

(-8,-8)

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Answer:

This is a guess!

When looking at the given equation I can not help but think of compound interest. So I am going to convert this into that format.

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Within the context of financial interest:

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8 0
3 years ago
PLEASE PLEASE PLEASE HELP. :(
mart [117]
Integers are like -4,-3,-2,-1,0,1,2,3,4 etc

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answer is 3rd one
7 0
2 years ago
Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ
marissa [1.9K]

Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

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3 years ago
If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

By the quadratic formula,

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Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

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Multiply numerator and denominator by the denominator's conjugate:

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3 years ago
Find measure dbc <br> 19<br> 22<br> 23<br> 161 <br> HELP !!!
uysha [10]
∠DBC = 19° since the two angles have to add up to 180, if x = 23, then 23 -4 = 19 for the right, and 7 x 23 = 161, and 161 + 19 = 180.
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