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Serggg [28]
3 years ago
12

5/6 plus 1 and 3/4 I need an answer to this

Mathematics
2 answers:
faltersainse [42]3 years ago
6 0
Answer:
= 2 7/12
=
2
7
12
Solution by separating parts
Rewriting our equation with parts separated
56+1+34
5
6
+
1
+
3
4
Solving the fraction parts
56+34=?
5
6
+
3
4
=
?
Find the LCD of 5/6 and 3/4 and rewrite to solve with the equivalent fractions.
LCD = 12
1012+912=1912
10
12
+
9
12
=
19
12
Simplifying the fraction part, 19/12,
1912=1712
19
12
=
1
7
12
Combining the whole and fraction parts
1+1+712=2712
1
+
1
+
7
12
=
2
7
12
mark me brainliest if this helps!!
Alexus [3.1K]3 years ago
3 0

Answer: 31/12

Step-by-step explanation:

7/4 + 5/6

42/24+ 20/24 = 62/24 = 31/12

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Answer:

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2 years ago
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LiRa [457]
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Consider a game in which a player rolls a number cube to determine the number of points earned. If a player rolls a number great
zhannawk [14.2K]
The probability of rolling any specific number is 1/6. The expected number of points is found from:
E(points) = (1/6 * -1) + (1/6 * -2) + (1/6 * -3) + (1/6 * 4) + (1/6 * 5) + (1/6 * 6)
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6 0
3 years ago
Find all real solutions:
Yakvenalex [24]
\frac{1}{x-1}+\frac{1}{x+2}=\frac{5}{4}|\cdot4(x-1)(x+2)\\
D:x\not=1 \wedge x\not=-2\\
4(x+2)+4(x-1)=5(x-1)(x+2)\\
4x+8+4x-4=5(x^2+2x-x-2)\\
8x+4=5x^2+5x-10\\
5x^2-3x-14=0\\
5x^2-10x+7x-14=0\\
5x(x-2)+7(x-2)=0\\
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6 0
3 years ago
Find all rational zeros of the polynomial
rjkz [21]

x^3+x^2-5x+3=x^3+3x^2-2x^2-6x+x+3\\\\=(x^3-2x^2+x)+(3x^2-6x+3)=x(x^2-2x+1)+3(x^2-2x+1)\\\\=(x^2-2x+1)(x+3)=\underbrace{(x^2-2(x)(1)+1^2)}_{(a-b)^2=a^2-2ab+b^2}(x+3)=(x-1)^2(x+3)\\\\P(x)=0\iff(x-1)^2(x+3)=0\iff(x-1)^2=0\ \vee\ (x+3)=0\\\\x-1=0\ \vee\ x-1=0 \vee\ x+3=0\\\\x=1\ \vee\ x=1\ \vee\ x=-3\\\\Answer:\ \boxed{x_1=1,\ x_2=1,\ x_3=3}

4 0
3 years ago
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