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Julli [10]
3 years ago
7

Who might be experiencing psychosis?

Physics
1 answer:
azamat3 years ago
8 0

Answer:C: Irma who isn't sure who she is and often has hallucinations

Explanation:

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I NEED some help please!
andrew11 [14]
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3 0
4 years ago
A 600g boulder has a density of 8 g/cm3. What is the volume of the boulder
Amiraneli [1.4K]
Density can be calculated using the following rule:
density = mass / volume

Since the density is given as 8 gm/cm^3 and the mass is given as 600 grams, therefore, all we need to do is substitute in the equation to get the value of the volume as follows:
8 = 600 / volume
volume = 600 / 8 = 75 cm^3
3 0
4 years ago
A baseball is thrown 50.0m in 3.0s, what is the average speed of the baseball? Calculated answer is 16.666667! What is the corre
castortr0y [4]

Answer:

20m/s

Explanation:

Given parameters:

Distance of throw = 50m

Time  = 3s

Unknown:

Average speed  = ?

Solution:

Average speed is distance divided by time;

  Average speed  = \frac{distance }{time}

Insert the parameters and solve;

  Average speed  = \frac{50}{3}   = 16.66667m/s  = 20m/s

5 0
3 years ago
red dwarf stars (stars between 0.08 and 0.5 solar masses) evolve very differently than other stars as they age because ____.
Alex_Xolod [135]

Red dwarf stars evolve very differently than other stars as they age because <u>their </u><u>interiors </u><u>are well mixed, through strong convection.</u>

<h3>What are red dwarf stars?</h3>

Red dwarf stars are the smallest and coolest kind of stars on the main sequence.

Red dwarf stars (stars between 0.08 and 0.5 solar masses) evolve very differently than other stars as they age because <u>their </u><u>interiors </u><u>are well mixed, through strong convection.</u>

Learn more about Red dwarf stars  here: brainly.com/question/3151458

#SPJ11

6 0
2 years ago
A particle is leaving the Moon in a direction that is radially outward from both the Moon and Earth.
Misha Larkins [42]

Answer:

2780m/s

Explanation:

Essentially, Kinetic energy of the particle must equal the combined potential energies of earth and the moon when the object is on the moon's surface, meaning the full equation is

<h3>\frac{1}{2} mv^2=\frac{G(M_E)m}{r_E} +G\frac{M_mm}{r_m}\\</h3><h3 />

M_E=Mass of Earth=5.97*10^2^4

M_m=Mass of Moon=7.4*10^2^2kg

r_E=distance from earth's center to the moon's=3.84*10^8m

r_m=radius of moon=1.738*10^6m

After some algebra, the equation simplifies to

v=\sqrt{2G*(\frac{M_E}{r_E+r_m}+\frac{M_m}{r_m})}

Plugging in the values of G, which is 6.67*10^-^1^1 \frac{m^3}{kg*s^2}, should yield the proper answer of 2780m/s.

4 0
3 years ago
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