Answer:
a) 29.36 m
b) 2.44 s
c) 2.57 s
d) 25.117 m/s
Explanation:
t = Time taken
u = Initial velocity = 24 m/s
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
b)
Time taken by the ball to reach the highest point is 2.44 seconds
a)
The highest point reached by the ball above its release point is 29.36 m
c) Total height is 3+29.35 = 32.35 m
The ball reaches the ground 2.57 seconds after reaching the highest point
d)
The ball will hit the ground at 25.2117 m/s
T1 = 2×W / squrt (3) +1
T2 = squrt(6) ×W/ squrt (3) +1
Here, T1 is along A.
T2 is along B
W = 250N.
Yo can directly use above formula to find solution.
Answer:
concave surface!
Explanation: Hope This Helps :)