A fixed mass of gas has a volume of 25 cm³. The pressure of the gas is 100 kPa.
1 answer:
Answer:
67 kPa
Explanation:
Given that,
Initial volume, V₁ = 25 cm³
Initial pressure, P₁ = 100 kPa
Final volume, V₂ = 15 cm³
We need to find the change in pressure of the gas. The relation between the volume and pressure of a gas is given by :
or
= 167 kPa
The change in pressure,
= P₂ - P₁
= 167 kPa - 100 kPa
= 67 kPa
Hence, the correct option is (a).
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Answer:
Stretch can be obtained using the Elastic potential energy formula.
The expression to find the stretch (x) is
Explanation:
Given:
Elastic potential energy (EPE) of the spring mass system and the spring constant (k) are given.
To find: Elongation in the spring (x).
We can find the elongation or stretch of the spring using the formula for Elastic Potential Energy (EPE).
The formula to find EPE is given as:
Rewriting the above expression in terms of 'x', we get:
Example:
If EPE = 100 J and spring constant, k = 2 N/m.
Elongation or stretch is given as:
Therefore, the stretch in the spring is 10 m.
So, stretch in the spring can be calculated using the formula for Elastic Potential Energy.