Answer:
The factorization of
is 
Step-by-step explanation:
This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form
or
. It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).
Let's solve the factorization of
by using the <em>sum and difference of cubes </em>factorization.
1.) We calculate the cubic root of each term in the equation
, and the exponent of the letter x is divided by 3.
![\sqrt[3]{729x^{15}} =9x^{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B729x%5E%7B15%7D%7D%20%3D9x%5E%7B5%7D)
then ![\sqrt[3]{10^{3}} =10](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B10%5E%7B3%7D%7D%20%3D10)
So, we got that
which has the form of
which means is a <em>sum of cubes.</em>
<em>Sum of cubes</em>

with
y 
2.) Solving the sum of cubes.


.
Answer:
6
Step-by-step explanation:
find a common factor
6*8=48
8*6=48
Answer:
(-3, -4).
Step-by-step explanation:
-4x + y = 8
x - 5y = 17 Multiply this by 4:
4x - 20y = 68 Add this to the first equation:
-19y = 76
y = 76/-19
y = -4.
Plug this into the second equation:
x - 5(-4) = 17
x = 17 - 20
x = -3.
CHECK this result in equation 1:
-4(-3) + -4 = 8
12 - 4 = 8
8 = 8 <------ OK.
Answer:
43.8 km to the nearest tenth.
Step-by-step explanation:
5 miles is 8 km
so 1 mile = 8/5 km
and 27.4 miles = 27.4 * 8/5
= 43.84 km
Answer:
Step-by-step explanation:
We know that between 1 to 10 there are 5 even and 5 odd numbers.
We could get 4 even cards , 4 odd cards or 2 odd and 2 even cards
Let´s check all this combinations
Case 1: When all 4 numbers are even:
We are going to take 4 of the 5 even numbers in the box so we have

Case 2: When all 4 numbers are odd:
We are going to take 4 of the 5 odd numbers in the box, so we have

Case 3: When 2 are even and 2 are odd:
We are giong to take 2 from 5 even and odd cards in the box so we have

Remember that we obtain the probability from
So we have the number of favourable outcomes but we need the Total cases for drawing four cards, so we have that:
We are taking 4 of the 10 cards:

Hence we have that the probability that their sum is even
