Answer:
424.26 m/s
Explanation:
Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q
The relative speed will be calculated by using pythagorean theorem
Relative speed = sqrt(300^2 + 300^2)
Relative speed = sqrt( 180000 )
Relative speed = 424.26 m/s
Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s
Answer:
10880N
Explanation:
We are given that
Mass of elevator, m=850 kg
Acceleration, 
We have to find the tension in the cable.
We know that
When elevator is accelerating upward then tension in the cable
Using the formula
It will depend on the frictional force involved in the two. I think it will take more force in sled.
When an electric current flows, it produces magnetic field. The strength of the magnetic field depends on the amount of charge flowing per second. The direction of the magnetic depends on the direction of flow of electric current. So, the direction of magnetic field changes when the direction of current/charges changes.
Answer:
-4892 J
Explanation:
The work done by friction is equal to the difference in mechanical energy of the car between the bottom of the loop (point A) and the top of the loop (point B).
The mechanical energy of the car at point A is
where
is the mass of the car
is the speed at point A
is the height of the car at point A (zero because it is at the bottom of the loop)
Substituting into the equation, we find
The mechanical energy of the car at point B is
where
is the mass of the car
is the speed at point B
(twice the radius) is the height of the car at point B, at the top of the loop
Substituting into the equation, we find
So, the work done by friction is
And the work is negative because it is done against the motion of the car.
