Answer: It was a big learning platformed and influenced millions of people. Without it we wouldnt be where we are today
Explanation:
Answer:
6.384 m/
Explanation:
The velocity is given by;
We know;
PE= mgh
KE= 1/2 m
but KE=PE
==> 1/2 m =mgh
==> 1/2 =gh
==>
puting g=9.8 m/sec2
h=2.08 m
==> =
Answer:
the moment of inertia of the merry go round is 38.04 kg.m²
Explanation:
We are given;
Initial angular velocity; ω_1 = 37 rpm
Final angular velocity; ω_2 = 19 rpm
mass of child; m = 15.5 kg
distance from the centre; r = 1.55 m
Now, let the moment of inertia of the merry go round be I.
Using the principle of conservation of angular momentum, we have;
I_1 = I_2
Thus,
Iω_1 = I'ω_2
where I' is the moment of inertia of the merry go round and child which is given as I' = mr²
Thus,
I x 37 = ( I + mr²)19
37I = ( I + (15.5 x 1.55²))19
37I = 19I + 684.7125
37I - 19 I = 684.7125
18I = 684.7125
I = 684.7125/18
I = 38.04 kg.m²
Thus, the moment of inertia of the merry go round is 38.04 kg.m²
1) 6 degrees per second ( you can convert it from degrees it that's not what you're looking for)
2) .47 cm per sec
Answer:
a) Resistivity=R.A/L
Here, R=500000ohm, L=1.6m, A=2pi* (0.14/2)*0.002 m2=0.00088.........we have converted quantities into SI units
Resistivity=R.A/L
=500000*0.00088/1.6 = 440/1.6= 275 ohm.meter
b) pskin/pinterior =275/4.8=57.3
For second part, correct option is (A), because cross section area is smaller.