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2 years ago

14

What type of numbers can be written as a fraction. This includes repeating and terminating decimals * Natural Numbers O Whole Nu

mbers O Integer Numbers O Rational Number

1 answer:

ArbitrLikvidat [17]2 years ago

4 0

Answer: the answer is rational because there is a finite(limited) number of numbers when written as a decimal .

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crimeas [40]

Answer:

..............................................yes

Step-by-step explanation:

lol

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2 years ago

What is the solution to the inequality |X-4 <3?

kobusy [5.1K]

Answer:

x<7

therefore {x:x<7}

Step-by-step explanation:

x-4<3

x<3+4

x<7

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2 years ago

Find the radius of the circle with a diameter of 8 inches.

Paladinen [302]

Answer:

4 inches

Step-by-step explanation:

The radius of a circle is its diameter divided by 2.

8/2 = 4

Ans = 4 inches

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2 years ago

Solve the following initial value problem.

Ymorist [56]

For starters,

$\cos(6t+\pi) = \cos(6t) \cos(\pi) - \sin(6t) \sin(\pi) = -\cos(6t)$

Now by the fundamental theorem of calculus, integrating both sides gives

$\displaystyle \frac{ds}{dt} = s'(0) + \int_0^t 36 \cos(6u) \, du = 100 + 6 \sin(6t)$

Integrating again, we get

$\displaystyle s(t) = s(0) + \int_0^t (100 + 6\sin(6u)) \, du = \boxed{100t - \cos(6t) + 1}$

Alternatively, you can work with antiderivatives, then find the particular constants of integration later using the initial values.

$\displaystyle \int \frac{d^2s}{dt^2} \, dt = \int 36\cos(6t) \, dt \implies \frac{ds}{dt} = 6\sin(6t) + C_1$

$\displaystyle \int \frac{ds}{dt} \, dt = \int (6\sin(6t) + C_1) \, dt \implies s(t) = -\cos(6t) + C_1t + C_2$

Now,

$s(0) = 0 \implies 0 = -1 + C_2 \implies C_2 = 1$

and

$s'(0) = 100 \implies 100 = 0 + C_1 \implies C_1 = 100$

Then the particular solution to the IVP is

$s(t) = -\cos(6t) + 100t + 1$

just as before.

4 0

1 year ago

Order from greatest to least. 4. -4. 9. -7 *

Sergeu [11.5K]

Answer

9 4 -7 -4

Step-by-step explanation:

7 0

2 years ago