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Bezzdna [24]
3 years ago
10

Chemical equations

Chemistry
2 answers:
Alenkasestr [34]3 years ago
7 0

I believe it is B writing chemical formulas

Yuki888 [10]3 years ago
4 0

chemical equations: describe chemical reactions

Answer: a

I think this is the answer

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What is the SI unit used to measure the temperature of a substance?
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The SI unit for temperature is Kelvin.

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An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?
umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

6 0
3 years ago
WILL GIVE BRANLIEST!! EASY BUT I WAS TO LAZY TO LEARN!! WILL FOREVER BE GREATFUL!!! WILL GIVE BRANLIEST!! EASY BUT I WAS TO LAZY
maxonik [38]

Answer:

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pH + 10 = 14

pH = 14 - 10

pH = 4

<u>-TheUnknownScientist</u>

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3 years ago
In the picture this is my last question pls.
Genrish500 [490]

Answer:

Chromosomes and I think its too many

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