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Alexxx [7]
3 years ago
6

INSIG

Chemistry
1 answer:
vazorg [7]3 years ago
3 0

Answer:

The given statement shows that the two families knew each other. Some people had left their home due to the war many years ago. Those who had stayed back thought that the ones who had left would never come back. That is why the woman feels surprised to see one of them come back. It also shows that selfishness of human behavior. People care for material things done for human beings. But it can't be said of all human beings. The narrator and her mother were totally different in their nature. They were trusting and loving human beings. Thus the given statement does give some clue about the story.

previously answered by brainly verified user

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Moles of NaOH used in titration mole NaOH Moles of HC2H3O2 neutralized by NaOH mole HC2H3O2 Molarity of HC2H3O2 M HC2H3O2 Grams
Marta_Voda [28]

For the given picture:

Moles of NaOH = A × 0.04183 moles

Moles of HC2H3O2 neutralized = (A × 0.04183) moles

Mass of HC2H3O2 = (2.0598 × A)g

Percent (m/v) HC2H3O2 in vinegar = (411.96 × A)%

<h3>What is molarity?</h3>

A mole is the unit of measurement used for chemicals, hence the term "molarity". Molarity, also known as solution molarity, is a technique for calculating the amount of a substance in a particular chemical solution.

Let molarity of NaOH be A from picture, volume of vinegar used is 5ml.

Now, average volume of NaOH used for titration = 0.04183 L (as per picture)

Molarity of NaOH = A

So,

(C7) Moles of NaOH = A × 0.04183

as 1 mol NaOH neutralizes 1 mol CH3COOH

(A × 0.04183) moles will neutralize (M × 0.04183) moles CH3COOH

(C8) moles of HC2H3O2 neutralized = (A × 0.04183)

Molar mass of HC2H3O2 is 60 gm/mol

So mass of (M × 0.04183) moles is (A × 0.04183 × 60) = (2.0598 × A)

(C9) Grams HC2H3O2 = (2.0598 × A)

Now volume of (vinegar+acetic acid) that was titrated = 5ml or 0.005 L

Now, M₁V₁ = M₂V₂

where,

M₁ = A

V₁ = 0.04183L

M₂ = ?

V₂ = 0.005L

put all values, value of V must be in liters

M₂ = (0.04183 × A)/0.005 = 8.366A Molar

(C10) molarity of HC2H3O2 = 8.366A Molar

Now grams of HC2H3O2 is taken from C9 and volume of vinegar is 0.005L

(C11)so mass of acetic acid/volume of vinegar(m/v)

= [(2.0598 × A)/0.005]

= (411.96 × A)%

To know more about molarity, visit:

brainly.com/question/2817451

#SPJ1

The complete question is as follows:

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