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Jlenok [28]
3 years ago
10

How many milliliters of 0.260 m na2s are needed to react with 35.00 ml of 0.315 m agno3?

Chemistry
1 answer:
allochka39001 [22]3 years ago
6 0

The complete balanced chemical reaction is:

2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S

 

First let us calculate the number of moles of AgNO3.

moles AgNO3 = 0.315 M * 0.035 L

moles AgNO3 = 0.011025 mol

 

From the reaction, 1 mole of Na2S is needed for every 2 moles of AgNO3 hence:

moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2 mol AgNO3)

moles Na2S required = 5.5125 x 10^-3 mol

 

Therefore volume required is:

volume Na2S = 5.5125 x 10^-3 mol / 0.260 M

<span>volume Na2S = 0.0212 L = 21.2 mL</span>

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Answer: 0.113 moles of NaCl are created as a result of decomposing 12 grams of NaClO_3.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} NaClO_3=\frac{12g}{106.5g/mol}=0.113moles

The balanced chemical equation for decomposition of NaClO_3 is:

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According to stoichiometry :

2 moles of NaClO_3 give = 2 moles of NaCl

Thus 0.113 moles of NaClO_3 give =\frac{2}{2}\times 0.113=0.113moles  of NaCl

Thus 0.113 moles of NaCl are created as a result of decomposing 12 grams of NaClO_3.

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How many molecules of Ca are found in a sample with 0.2 mols?
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\boxed{1.2 \times 10^{23}\text{ atoms}}

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Explanation:

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An atom that has 13  protons and 15  neutrons  is isotope  of Aluminium (answer C)

<u><em>Explanation</em></u>

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  • In other words isotope has the same  atomic number but different mass  number.
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