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Nadusha1986 [10]
3 years ago
9

What would be the mass of 3 moles of water molecules?

Chemistry
2 answers:
ankoles [38]3 years ago
7 0

Answer:

\boxed {\boxed {\sf A. \ 54 \ grams }}

Explanation:

To convert from moles to grams, we must use the molar mass.

Recall that water's molecular formula is H₂O. It contains hydrogen and oxygen. Look up the two elements masses on the Periodic Table.

  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 15.999 g/mol

Now, use these masses to find water's mass. The subscript of 2 tells us there are 2 atoms of hydrogen, so we multiply hydrogen's mass by 2 and add oxygen's.

  • H₂O= 2(1.008 g/mol) + 15.999 g/mol = 18.015 g/mol

Use the molar mass as a ratio.

\frac{18.015 \ g \ H_2 O}{ 1 \ mol \ H_2 O}

Multiply by the given number of moles.

3 \ mol \ H_2O*\frac{18.015 \ g \ H_2 O}{ 1 \ mol \ H_2 O}

The moles of water will cancel.

3 *\frac{18.015 \ g \ H_2 O}{ 1 }

3 *{18.015 \ g \ H_2 O}

54.045 \ g \ H_2O

Round to the nearest whole number. The 0 in the tenth place tells us to leave the number as is.

54 \ g \ H_2O

There are about <u>54 grams</u> of water in 3 moles.

frez [133]3 years ago
7 0

Answer:

54 grams

Explanation:

First step is to find what one mole of water is in grams.

Water is H2O so that means we have two moles of Hydrogen.

H - 2 grams (on periodic table)

We have one mole of Oxygen.

O - 16 grams (on periodic table)

Add 2 and 16 to get 18 total grams in one molecule of H2O

Now multiply 3 times 18 to know how many grams in 3 moles of H2O

You end with

3x18=54 grams

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5 0
2 years ago
Please help me. I can’t give too much points bc I don’t have too much.
zubka84 [21]
Answer is photons hope this helps
7 0
3 years ago
Which of the following molecules or ions is polar? (20 POINTS)
taurus [48]

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3.   Nitrate (NO3-)ion  geometry would be trigonal planar

<u>For CCl4 molecule(fig.2)</u>

1. Bonds are created between elements with different electronegativity, most bonds would be polar. Bonds in CCl4 are polar.

2. It is a completely symmetrical molecule.

3.Carbon is the centre of CCl4 have four covalent bonds and it has no lone pairs. They are all equidistant the C-Cl bond polarities cancel out. So CCl4 molecule is non polar

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1. Bonds are created between elements with different electronegativity, most bonds would be polar. Bonds in NH3 molecule are polar.

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4 years ago
The first species that colonizes new or undisturbed land is called a _______ species. A. predecessor B. premier C. pioneer D. pr
Bond [772]
They would be called a pioneer species.
5 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
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