Answer:
D:) (2,2,) is the Answer
Step-by-step explanation:
Solve the following system:
{X - 2 Y = -2 | (equation 1)
{3 X - 2 Y = 2 | (equation 2)
Swap equation 1 with equation 2:
{3 X - 2 Y = 2 | (equation 1)
{X - 2 Y = -2 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 X - 2 Y = 2 | (equation 1)
{0 X - (4 Y)/3 = (-8)/3 | (equation 2)
Multiply equation 2 by -3/4:
{3 X - 2 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Add 2 × (equation 2) to equation 1:
{3 X+0 Y = 6 | (equation 1)
{0 X+Y = 2 | (equation 2)
Divide equation 1 by 3:
{X+0 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Collect results:
Answer: {X = 2 , Y = 2
Answer:
(8, 15 and 17)
Step-by-step explanation:




The <u>correct answers</u> are:
6.5 cm = 65.00001052 torr
6.5 cm = 8665.93 Pa
6.5 cm = 0.08552632119 atm
Explanation
The conversion rate from centimeters mercury (cm Hg) to torr is
1 torr = 0.099999983814461 cm.
We have 6.5 cm; this means to convert we divide:
6.5/0.099999983814461 = 65.00001052
The conversion rate from cm Hg to Pascals (Pa) is
1 cm = 1333.22 Pa
We have 6.5 cm; this means to convert we multiply:
6.5(1333.22) = 8665.93
The conversion rate from cm Hg to atmospheres (atm) is
1 atm = 75.999995199606 cm
We have 6.5 cm; this means to convert we divide:
6.5/75.999995199606 = 0.08552632119
Answer:
The distance covered is 113.75 m
Step-by-step explanation:
As per the question:
The initial velocity of the train, v = 20 m/s
The final velocity of the train, v' = 6 m/s
Uniform deceleration, a = 1.6
Or uniform acceleration, a = - 1.6
<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>
Now, to find the distance covered, s:
Using the eqn of Kinemetics:




Answer:
The volume of cube is 125 cm³.
Step-by-step explanation:
Given that the formule of volume of cube is, V = length×width×height. Cube is a 3D form of square, so the sides of the cube are all the same. You have to substitute 5 into the formula,
Let length be 5 cm,
Let width be 5 cm,
Let height be 5 cm,
Volume = 5×5×5
= 125 cm³