All categories

3 years ago

How do you identify the three different types of asymptotes?

Mathematics

2 answers:

Sveta_85 [38]3 years ago

6 0

Answer:

There are three kinds of asymptotes: horizontal, vertical and oblique asymptotes. For curves given by the graph of a function y = ƒ(x), horizontal asymptotes are horizontal lines that the graph of the function approaches as x tends to +∞ or −∞.

ozzi3 years ago

5 0

Answer:

Step-by-step explanation:

~Riley~

Google

Have a good day!

You might be interested in

One root of f(x)=x^3-9x^2+26x-24 is x = 2. What are all the roots of the function? Use the Remainder Theorem.

aniked [119]

Answer:

$x=3$ or $x=4$

Step-by-step explanation:

the given function is;

$f(x)=x^3-9x^2+26x-24$

According to the rational roots theorem, the possible rational roots are;

$\pm1,\pm2\pm3,\pm4,\pm6,\pm8,\pm12,\24$ .

According to the Remainder Theorem, if $f(a)=0$ , then $x=a$ is a zero of the polynomial.

$f(3)=3^3-9(3)^2+26(3)-24$

$f(3)=27-81+78-24$

$f(3)=24-24=0$

Also,

$f(4)=4^3-9(4)^2+26(4)-24$

$f(4)=64-144+104-24$

$f(4)=64-64=0$

Therefore the other roots are;

$x=3,x=4$

7 0

3 years ago

The table shows various values of a linear function f (x).

mojhsa [17]

The value of f –1(13) is 4

<h3>How to determine the inverse value?</h3>

The table of values is given as:

x –4 0 2 5 9 13

f (x) –11 1 7 16 28 40

A linear function is represented as:

y = mx + b

Where b represents the y-intercept and m represents the slope

From the graph, when x = 0, y = 1.

This means that b = 1

So, we have

y = mx + 1

Also from the graph, when x = 2, y = 7.

So, we have:

7 = 2m + 1

Subtract 1 from both sides

7 - 1 = 2m + 1 - 1

Evaluate the difference

6 = 2m

Rewrite the above equation as:

2m = 6

Divide both sides of the equation by 2

m = 3

Substitute m = 3 in y = mx + 1

y = 3x + 1

The notation f –1(13) implies that y = 13

So, we have

13 = 3x + 1

Subtract by 1

3x = 12

Divide by 3

x = 4

Hence, the value of f –1(13) is 4

Read more about linear functions at:

brainly.com/question/4025726

#SPJ1

4 0

2 years ago

Y=tan ( cos ( pi t)+.5)+2

9966 [12]

Answer:

86.634

Step-by-step explanation:

8 0

2 years ago

Pleeeeese help me as fast as you can!!!

Aleonysh [2.5K]

Answer:

A. $y=3x-10$

C. $y+6=3(x-15)$

Step-by-step explanation:

Given:

The given line is $6x+18y=5$

Express this in slope-intercept form $y=mx+b$ , where m is the slope and b is the y-intercept.

$6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}$

Therefore, the slope of the line is $m=-\frac{1}{3}$ .

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

$y=3x-10$

On comparing with the slope-intercept form, we get slope as $m_{A}=3$ .

Now, $m\times m_{A}=-\frac{1}{3}\times 3=-1$ . So, option A is perpendicular to the given line.

Option B:

For lines of the form $x=a$ , where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as $m_{C}=3$ .

Now, $m\times m_{C}=-\frac{1}{3}\times 3=-1$ . So, option C is perpendicular to the given line.

Option D:

$3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}$

On comparing with the slope-intercept form, we get slope as $m_{D}=-\frac{1}{3}$ .

Now, $m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}$ . So, option D is not perpendicular to the given line.

8 0

3 years ago

What is the range of h?

guajiro [1.7K]

Answer:

C: The h(x)-values -3, -2, 2, and 4

Step-by-step explanation:

The range is the values that the output can take

The y values are -3, -2, 2,4

C: The h(x)-values -3, -2, 2, and 4

5 0

3 years ago