You can't change the sum by changing the grouping. Any way you cut it, you will always get 226, as you only have addition operations, and the commutative property [a+(b+c)=(a+b)+c] means that the sum will always be the same.
Answer:
p(x)
Step-by-step explanation:
Substitute x = 3 into each function and calculate the value.
p(3) = 2(3)² + 4(3) + 11 = 2(9) + 12 + 11 = 18 + 12 + 11 = 41
h(3) = 4(3) = 12
s(3) = 10(3) = 30
Thus p(x) = 41 is the largest value when x = 3
The answer is 9 thousand 8 hundred and 67
She will need 6 boxes so she will have 6 more boxes left over
