1. To solve this problem, it is important to know that<span> the logarithmic functions and the exponential functions are inverse. Then, you have:
</span><span>
e^a=28.37
</span><span> a=ln(28.37)
</span><span>
2. Therefore: </span><span>Which logarithmic equation is equivalent to the exponential equation e^a=28.37? A</span><span>s you can see, the answer for this question is:
</span><span>
a=ln(28.37)</span>
Answer:
The scale factor is 3.
Step-by-step explanation:
Take the new pupil size divided by the original pupil size
6.3/2.1 = 3
If this answer is correct, please make me Brainliest!
Answer:
2 11/12 or 35/12
Step-by-step explanation:
For the number 2 is -14x+6
For the number 1 is (2,3)
and I hope you that helps you!!!
5y + 2y = 22
(add 2y to 5y)
7y = 22
(divide each side by 7)
y ≈ 3.1
-2y + 6y = 3
(add 6y to -2y)
4y = 3
(divide each side by 4)
y = 0.75
