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4 years ago

Subtract 23° 19' 17° 9' ______

Mathematics

1 answer:

Delvig [45]4 years ago

3 0

Step-by-step explanation:

$\: \: \: \: 20 \degree \: \: 19' \: \\ - 17 \degree \: \: \: \: 9' \\ - - - - - - \\ \: \: \: \: \: 3 \degree \: \: \: \: 10' \\ - - - - - - -$

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Jane had 275 stickers, which she gave to her friends. Each friend got five more stickers than the friend before. If the first fr

Paha777 [63]

Answer:

10 friends

Step-by-step explanation:

we know that

The formula of the sum is equal to

$sum=\frac{n}{2}[2a1+(n-1)d]$

where

a1 is the first term

n is the number of terms (number of friends)

d is the common difference in the arithmetic sequence

In this problem we have

$sum=275\ stickers$

$a1=5\ stickers$

$d=5$ ----> the common difference

substitute in the formula and solve for n

$275=\frac{n}{2}[2(5)+(n-1)(5)]$

$550=n[10+5n-5]\\ \\550=10n+5n^{2} -5n\\ \\5n^{2}+5n-550=0$

Solve the quadratic equation by graphing

The solution is n=10

see the attached figure

therefore

She had 10 friends who got stickers

5 0

3 years ago

On the planet of Mercury, 4-year-olds average 3 hours a day unsupervised. Most of the unsupervised children live in rural areas,

erastova [34]

Answer:

The distribution of X is normal

$P(X < 1.4) = 0.12654$

$P(X > 3.5) = 0.36051$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 3 \ hours$

The standard deviation is $\sigma = 1.4 \ hours$

Generally given from the question that the amount of time spent alone by the population size is normally distributed then then the distribution of X (i.e the amount of time spent by the sample size (the one Mercurian)) will be normally distributed

Generally the probability that the child spend less than one hour in a day is mathematically represented as

$P(X < 1.4) = P(\frac{X - \mu}{\sigma} < \frac{1.4 - \mu}{\sigma} )$

Here $\frac{X - \mu}{\sigma } = Z (The\ standardized\ value\ of\ X)$

$P(X < 1.4) = P(Z < \frac{1.4 - 3.0}{1.4} )$

$P(X < 1.4) = P(Z < -1.1429 )$

From the z-table the value of

$P(Z < -1.1429 )=0.12654$

So $P(X < 1.4) = 0.12654$

Generally the percentage of children that spends over 3.5 hours unsupervised is mathematically represented as

$P(X > 3.5) = P(\frac{X - \mu}{\sigma} > \frac{3.5 - \mu}{\sigma} )$

$P(X > 3.5) = P(Z > \frac{3.5 - 3.0}{1.4} )$

$P(X > 3.5) = P(Z > 0.3571 )$

From the z-table the value of

$P(Z >0.3571 )=0.36051$

So $P(X > 3.5) = 0.36051$

5 0

3 years ago

HURRY QUICK!!! Find the solution set of the inequality.<br><br>8x - 8 < ( or equal to ) -72

slava [35]

I would take away the 8's, and that would leave x standing, so X could either be -72 or less than -72,

8 0

3 years ago

PLEASEEEEE HELP ME PLEASE WILL MAR AS BRANLIEST!!!!!!!!!!

mylen [45]

That is right. Angle 2 to side 2 to angle 1 for both of them.The second triangle is just the first upside down.

3 0

3 years ago

Help me please anyone!

olasank [31]

Answer:

1) 13(2) + 2m = A

2) 70

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Subtract 23° 19' 17° 9' ______ ​

Subtract 23° 19' 17° 9' ______