Step 1
Anything divided by one gives itself.
\frac{1}{8}=-8\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−8 and
1
−8
=
48
−12
Step 2
Convert -8−8 to fraction -\frac{64}{8}−
8
64
.
\frac{1}{8}=-\frac{64}{8}\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−
8
64
and
1
−8
=
48
−12
Step 3
Compare \frac{1}{8}
8
1
and -\frac{64}{8}−
8
64
.
\text{false}\text{ and }\frac{-8}{1}=\frac{-12}{48}false and
1
−8
=
48
−12
Step 4
Anything divided by one gives itself.
\text{false}\text{ and }-8=\frac{-12}{48}false and −8=
48
−12
Step 5
Reduce the fraction \frac{-12}{48}
48
−12
to lowest terms by extracting and canceling out 1212.
\text{false}\text{ and }-8=-\frac{1}{4}false and −8=−
4
1
Step 6
Convert -8−8 to fraction -\frac{32}{4}−
4
32
.
\text{false}\text{ and }-\frac{32}{4}=-\frac{1}{4}false and −
4
32
=−
4
1
Step 7
Compare -\frac{32}{4}−
4
32
and -\frac{1}{4}−
4
1
.
\text{false}\text{ and }\text{false}false and false
Step 8
The conjunction of \text{false}false and \text{false}false is \text{false}false.
\text{false}false
Hint
Do the arithmetic.
Solution
\text{false}false
Answer:
you divide the number by 60 and get 1.83333333 then you have 1 (whole number with 83333333/100000000
Step-by-step explanation:
7/33 as a decimal is <span>0.21212121212</span>
Function assign value from one set to another. The value of f(5), if f(1) = 3.2 and f(x+1) = Five-halves(f(x)) is 125.
<h3>What is Function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
As it is given the value of the function f(1) is 3.2, while the value of f(x+1) is ![f(x+1) = \dfrac{5}{2}[f(x)]](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D)
, therefore, in order to find the value of f(5), we need to calculate the value of f(4).
f(2)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(2)=f(1+1) = \dfrac{5}{2}[f(1)]\\\\f(2) = 2.5 \times 3.2\\\\f(2) = 8](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%282%29%3Df%281%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%281%29%5D%5C%5C%5C%5Cf%282%29%20%3D%202.5%20%5Ctimes%203.2%5C%5C%5C%5Cf%282%29%20%3D%208)
f(3)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(3)=f(2+1) = \dfrac{5}{2}[f(2)]\\\\f(3) = 2.5 \times 8\\\\f(3) = 20](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%283%29%3Df%282%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%282%29%5D%5C%5C%5C%5Cf%283%29%20%3D%202.5%20%5Ctimes%208%5C%5C%5C%5Cf%283%29%20%3D%2020)
f(4)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(4)=f(3+1) = \dfrac{5}{2}[f(3)]\\\\f(4) = 2.5 \times 20\\\\f(4) = 50](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%284%29%3Df%283%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%283%29%5D%5C%5C%5C%5Cf%284%29%20%3D%202.5%20%5Ctimes%2020%5C%5C%5C%5Cf%284%29%20%3D%2050)
f(5)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(5)=f(4+1) = \dfrac{5}{2}[f(4)]\\\\f(5) = 2.5 \times 50\\\\f(5) = 125](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%285%29%3Df%284%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%284%29%5D%5C%5C%5C%5Cf%285%29%20%3D%202.5%20%5Ctimes%2050%5C%5C%5C%5Cf%285%29%20%3D%20125)
Hence, the value of f(5), if f(1) = 3. 2 and f(x+1) = Five-halves(f(x)) is 125.
Learn more about Function:
brainly.com/question/5245372
Answer:
It should be C
Step-by-step explanation:
