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3 years ago

Represents the distance between -12 and -5 on a number line?

Mathematics

1 answer:

aivan3 [116]3 years ago

3 0

7 units between -12 and -5

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3 years ago

(8x + 11) - (7x - 5)?

zaharov [31]

Answer:

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Step-by-step explanation:

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3 years ago

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Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

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3 years ago

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Please help answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!

Whitepunk [10]

Answer:

i think its 360.......

Step-by-step explanation:

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3 years ago

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PLEASE HELP ASAP WILL GIVE BLAINLY PTS

ddd [48]

Answer:

$\large\boxed{C.\ \dfrac{2x-20}{x^2+6x-40}}$

Step-by-step explanation:

$f(x)=\dfrac{x-16}{x^2+6x-40}=\dfrac{x-16}{x+10x-4x-40}=\dfrac{x-16}{x(x+10)-4(x+10)}\\\\f(x)=\dfrac{x-16}{(x-4)(x+10)}\\\\g(x)=\dfrac{1}{x+10}\\\\f(x)+g(x)=\dfrac{x-16}{(x-4)(x+10)}+\dfrac{1}{x+10}=\dfrac{x-16}{(x-4)(x+10)}+\dfrac{1(x-4)}{(x-4)(x+10)}\\\\=\dfrac{x-16+x-4}{(x-4)(x+10)}=\dfrac{2x-20}{(x-4)(x+10)}=\dfrac{2x-20}{x^2+6x-40}$

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3 years ago