Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
Answer:
It is The answer is D
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the angles be 4x , 5x
4x + 5x = 180 { supplementary}
9x = 180
x = 180/9
x = 20
Larger angle= 5x = 5* 20 = 100
Lines that are parallel have the same slope, and the given line (y = 6x - 5) has a slope of 6; we are looking for a line with a slope of 6.
To form an equation for a line, you need to know the y-intercept (the point at which the line intersects the y-axis). The first step to finding the y-intercept is to plot the given point. After you've done that, count six units up (this is our slope) and one to the right; plot the point. Lastly, draw the line by connecting the points and see where the line intersects the y-axis.
My graph shows that the line intersects the y-axis at -17. All that's left now is to put our information together into an equation. I'm assuming the problem wants the equation in slope-intercept form; slope-intercept form is y = mx + b where m is the slope and b is the y-intercept, so it would look like this:
y = 6x -17
Hope this helps.
Answer:
(2,0)
Step-by-step explanation:
Simply plug in the coordinates. y= 3x - 6, so in this case 0= 3(2) - 6 or 0=0, making the point on the line. If the equation is not true like when using (0,3) and getting 3= -6, then the point is not on the line.
