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lakkis [162]
4 years ago
10

John and O'Neal are playing a board game in which they roll two number cubes. John needs to get a sum of 8 on the number cubes t

o win. O'Neal needs a sum of 11. If they take turns rolling the number cube, who is more likely to win?
Mathematics
2 answers:
finlep [7]4 years ago
4 0

Answer:

The Sum of 8

Step-by-step explanation:

Sergio [31]4 years ago
3 0
John is more likely to win since he only needs a sum of 8 while O'Neal needs a sum of 11. Within 2 rolls both could win, but O'Neal would need to roll at least one 6 and either a 5 or 6 to win in two turns while John could roll a 2 and 6, 3 and 5, 4 and 4 and so on. John has a wider range of numbers he could roll to win
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It takes Jamil 40 minutes to drive to work, plus or minus 8 minutes depending on traffic. Which of the following equations could
gtnhenbr [62]

Answer:

addition

Step-by-step explanation:

add 40+8 and you get 48 :P

8 0
4 years ago
2 Name the diameter of the circle shown. <br>A co <br>B ec<br>C eo<br>D rc​
Orlov [11]

Answer: a

Step-by-step explanation:

6 0
3 years ago
Using the cross multiplication method, which of the following is the solution to 11/(2x+5) = 12/2x?
garri49 [273]

Answer:

x = -30 so it's D

Step-by-step explanation:


7 0
3 years ago
A zucchini plant in Darnell’s garden was 10 centimeters tall when it was first planted. Since then, it has grown approximately 0
Mariulka [41]

Answer:

Let's start with part B. if it was originally 10 cm tall and it goes up 0.5 cm. each day, then we know that to go up one cm it needs two days. With that information we can say that 8*2 = 16. So it needs 17 days to go up 8.5 cm which would make it 18.5 cm tall.

Step-by-step explanation:

f(x) = 0.5x + 10

0.5x + 10 = 18.5

0.5x = 18.5 - 10

0.5x = 8.5

x = 8.5/0.5

x = 17 days

6 0
3 years ago
A/ab-bsquare + b/ab-asquare?​
lord [1]

Answer:

\dfrac{(a+b)}{ab}

Step-by-step explanation:

The given expression is :

\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}

It can be solved as follows :

\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}

So, the solution of the given expression is equal to \dfrac{(a+b)}{ab}.

7 0
3 years ago
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