Well if you have the coordinates (2,2) and (4,4) you plug in the y from the second cords for y2
So it would be 4-2/4-2 and 2/2 equals 1
1 would be the m in y=MX+b
Then plug one set of coords in y=MX+b
2=1x+b
I know it's confusing to understand but I tried lol
Answer:
A 2
Step-by-step explanation:
When we divide x by 9 there is some whole number we will call y plus a remainder of 4
x/9 = y remainder 4
Writing this in fraction form
x/9 = y + 4/9
Multiplying each side by 9
9*x/9 = 9* y + 4/9 *9
x = 9y +4
Multiply each side by 2
2x = 2*(9y+4)
2x = 18y +8
Add 3 to each side
2x+3 = 18y +8+3
2x+3 = 18y +11
Divide each side by 9
(2x+3)/9 = 18y/9 +11/9
= 2y + 9/9 +2/9
=(2y+1 + 2/9)
We know y is a whole number and 1 is a whole number so we can ignore 2y +1 when looking for a remainder)
2/9 is a fraction
Taking this back from fraction form to remainder from
(2y+1) remainder 2
Answer:
1st option
Step-by-step explanation:
let y = f(x) and rearrange making x the subject
y = 2x + 1 ( subtract 1 from both sides )
y - 1 = 2x ( divide both sides by 2 )
= x
Change y back into terms of x with x being the inverse h(x)
h(x) = 
= 
x -
Answer:
Step-by-step explanation:
Find the measure of the vertex angle ∠ABD of an isosceles triangle
we know that
An isosceles triangle has two equal sides and two equal angles
In this problem
∠ABD=∠BAD= ----> the angles of the base are equals
Find the measure of the vertex angle
∠ABD= ------> the sum of the internal angles of a triangle is equal to
Step 2
Find the measure of the angle ∠CBD in the equilateral triangle
we know that
A equilateral triangle has three equal sides and three equal angles
The measure of the internal angle in a equilateral triangle is
so
∠CBD=
Step 3
Find the measure of the angle ∠ABC
∠ABC=∠ABD+∠DBC
substitute the values
∠ABC=
therefore
the answer is
the measure of the angle ∠ABC is
Area = length · width
Area = 3ft · 2ft
Area = 6ft²
hope this helps!
