Answer:
484,000
Step-by-step explanation:
The hundreds place is less than 5 so you round down.
Answer:
-14
Step-by-step explanation:
difference between -20 and -5 = 15
15 x 2/5 = 30/5 = 6
-20 + 6 = -14
Answer:
$342.30
Step-by-step explanation:
The original price of the computer is $489. The computer is discounted 30%, which means that 30% of the price is removed from the original price.
30% of 489 is
489 * 0.3 which is $146.7
146.7 is the discounted amount, not the selling price. To find the selling price, subtract how much is discounted ( 146.7) from the original price (489).
489-146.7= 342.3
Answer:
I think its A
Step-by-step explanation:
I factored the polynomial and its factors turned out to be (x-1)(x^2-2x-4), which eliminated the possibilities of 2 and 3. Then i replaced the (-1) in the place of the x and it turned out to be equal to 2, making the first statement true.
Answer:
a) = 4.5
b) = 3.3
Step-by-step explanation:
Before solving our problems given to us let us under stand the rule of cube roots
It says ![\sqrt[3]{x \times x \times x} = x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%20%5Ctimes%20x%20%5Ctimes%20x%7D%20%3D%20x)
-----(A)
Also
![\sqrt[3]{x \times x \times x \times y \times y \times y} = x \times y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%20%5Ctimes%20x%20%5Ctimes%20x%20%5Ctimes%20y%20%5Ctimes%20y%20%5Ctimes%20y%7D%20%3D%20x%20%5Ctimes%20y)
---(B)
Now let us see each part one by one
a) we have
![\sqrt[3]{64} + \sqrt[3]{0.027} + \sqrt[3]{0.008}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%2B%20%5Csqrt%5B3%5D%7B0.027%7D%20%2B%20%5Csqrt%5B3%5D%7B0.008%7D)
Now 64 = 4 x 4 x 4
0.027 = 0.3 x 0.3 x 0.3
0.008 = 0.2 x 0.2 x 0.2
substituting these values
![\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%20%5Ctimes%204%20%5Ctimes%204%7D%20%2B%20%5Csqrt%5B3%5D%7B0.3%20%5Ctimes%200.3%20%5Ctimes%200.3%7D%20%2B%20%5Csqrt%5B3%5D%7B0.2%20%5Ctimes%200.2%20%5Ctimes%200.2%7D)
Applying Rule A in above
4.5
b) we have ![\sqrt[3]{0.3 \times 0.3 \times 0.3 \times 11 \times 11 \times 11}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.3%20%5Ctimes%200.3%20%5Ctimes%200.3%20%5Ctimes%2011%20%5Ctimes%2011%20%5Ctimes%2011%7D)
Applying the B rule in this
3.3
