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Kryger [21]
3 years ago
10

____ occurs when the vapor pressure of a liquid is equal to the external atmospheric pressure.

Chemistry
2 answers:
ExtremeBDS [4]3 years ago
7 0

c.boiling

choice number 3

AlexFokin [52]3 years ago
4 0

Answer:

Boiling

Explanation:

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Look at the image shown. What does this image represent?
JulijaS [17]

Answer:

Linear molecule with two domains

Explanation:

8 0
3 years ago
2002040_MIJ COMP SCI 1_SEM 1 CR_PY
Slav-nsk [51]

Answer:

a scientific question

Procedure

Conclusion.

Explanation:

Scientific investigation is usually carried out to explain and give answers to natural phenomenon. Now, this scientific investigation is performed through the three main types as described in the question.

With that being said, the most common parts of all types of investigation are :

1. Scientific question: In this stage, questions are usually asked on the basis of observation made which could be answered.

2. Procedure: In this stage, the dimension of the steps are followed to answer and test the scientific question.

3. Conclusion: This is the primary aim that we check when done with our sample values

4 0
3 years ago
Part D
Basile [38]

The heat lost by copper(ii) sulfate is equal to heat absorbed by water since the total energy in the system remains constant according to the law of conservation of energy.

<h3>How can the number of moles be determined?</h3>

The number of moles of a substance is determined using the formula below:

  • Number of moles = mass/molar mass

Assuming the mass of copper(ii) sulfate used is <em>Mc</em>, number of moles of copper(ii) sulfate used is:

  • Moles of copper(ii) sulfate = <em>Mc</em>/159.60 moles

The heat absorbed by water is calculated using the formula below:

  • Quantity of Heat, H = mass × specific heat capacity × temperature change

mass of water <em>=</em><em> </em> 10 g

Let temperature change be <em>Tc</em>

Heat<em> </em>absorbed<em> </em>by water = 10 × 4.186 × Tc = 41

86Tc

The change in internal energy, ΔU of copper(ii) sulfate, is given as:

  • ΔU = Q − W

where:

Q =  heat absorbed by water

W  =  work done by or on the system

The enthalpy of the reaction is given as:

  • ΔH= energy released or absorbed/moles of copper (ii) sulfate

Therefore, according to the law of conservation of energy, the total energy in the system remains constant.

Learn more about internal energy change at: brainly.com/question/14126477

5 0
2 years ago
Which type of reaction is described by the following equation? Na2O (s) + 2CO2 (g) + H2O (g) produces 2NaHCO3 (s)
TiliK225 [7]

Answer:

If the reaction is going from left to right it would be synthesis, if going right to left it would be decomposition.

Explanation:

Na2O (s) + 2CO2 (g) + H2O (g) = 2 NaHCO3 (s)

Left Side

Na = 2

O = 6

C = 2

H = 2

Right Side

Na = 2

O = 6

C = 2

H = 2

Ok so is balanced already, though initial equation in question had an error in regards to the left hand side the ) should have been an O.

Hmm

Na2O (s) + 2CO2 (g) + H2O (g) = 2 NaHCO3 (s)

If it was going from right to left would be decomposition

But going from left to right it would be synthesis

8 0
3 years ago
If 28 ml of 5.4 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?
Ainat [17]

A reaction between acid and base to form water and salt is known as neutralization reaction. It is a double replacement reaction.  

The reaction between H_2SO_4 and NaHCO_3 will be:

H_2SO_4 + NaHCO_3 \rightarrow Na_2SO_4 + CO_2 + H_2O

The balanced reaction is:

H_2SO_4 + 2NaHCO_3 \rightarrow Na_2SO_4 + 2CO_2 + 2H_2O

Volume of H_2SO_4 = 28 mL (given)

Since, 1 L = 1000 mL

So, 28 mL = 0.028 L

Molarity of H_2SO_4 = 5.4 M (given)

Molarity = \frac{number of moles of solute}{Volume of solution in Liters}   -(1)

Substituting the values in equation (1):

5.4 mol/L = \frac{number of moles of H_2SO_4}{0.028 L}

number of moles of H_2SO_4 = 5.4 mol/L\times0.028 L

number of moles of H_2SO_4 = 0.1512 mol

From the balanced reaction between H_2SO_4 and NaHCO_3, 2 moles of NaHCO_3 reacts with 1 mole of H_2SO_4.

Molar mass of NaHCO_3 = 84.007 g/mol

Mass of NaHCO_3 needed:

0.1512 mol H_2SO_4 \times \frac{2 mole NaHCO_3}{1 mole H_2SO_4}\times \frac{84.007 g}{1 mole NaHCO_3} = 25.404 g

Hence, the required amount of NaHCO_3 is 25.404 g.


7 0
3 years ago
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