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sergey [27]
3 years ago
13

Richard wrote a list of the advantages of using any one of the six simple machines. His list is below. Which statement about sim

ple machines is not correct?
A.
Some simple machines produce an output force greater than the input force.
B.
Some simple machines produce an output force in a different direction than the input force.
C.
Some simple machines have a work output greater than the work input.
D.
Some simple machines increase the distance through which a force is applied.

Plss say just A,b,c, or d :/
Chemistry
1 answer:
alekssr [168]3 years ago
6 0

Answer:

c

Explanation:

just took the test 100 on it the test is simple machines

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(B) Her results are both precise and accurate.

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In the above question, all the above results are very close to each other. That's why the results are Precise to each other. All the results  are close enough to the actual value of the experiment. That's why the result are also accurate.

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A mole is defined to be____particles of a substance.
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Aspirin that has been stored for a long time may give a vinegar like odour and give a purple colour with FeCl3. What reaction wo
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See explanation

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3 0
3 years ago
What is the h oh ph and poh of a 0.005m solution of calcium hydroxide?
fiasKO [112]

Answer: [OH^{-}]= 0.01M or 1.0\times 10^{-2}M

[H^{+}]= 1.0\times 10^{-12}M

pH = 12

pOH = 2

Explanation: Calcium hydroxide (Ca(OH)_{2}) is a strong base that dissociates completely.

Dissociation equation of Calcium hydroxide is :

Ca(OH)_{2} \rightarrow Ca^{+2} + 2OH^{-}

1. Concentration of [OH-]

1 mol Ca(OH)_{2} produces 2 mol OH- ions.

The given solution is 0.005M Ca(OH)_{2} , then  concentration of OH- would be twice the concentration of Ca(OH)_{2}

[OH^{-}] = 0.005\times 2 = 0.01M or 1.0\times 10^{-2}M

2.Concentration of [H+]

Concentration of [H+] can be calculated by the formula: [H^{+}] = \frac{Kw}{[OH^{-}]}

kw = ionic product of water and its values is (1\times 10^{-14})

[OH-] = 0.01 M or 1.0\times 10^{-2}M

[H^{+}] = \frac{(1\times 10^{-14})}{[OH^{-}]}

[H^{+}] = \frac{(1\times 10^{-14})}{[0.01]}

[H^{+}] = 1.0\times 10^{-12}M

3. pH value

pH is calculated by the formula : pH = -log[H^{+}]

pH = -log[1.0\times 10^{-12}]

pH = 12

4. pOH value

pOH is calculated by the formula : pOH = 14 - pH

pOH = 14 - 12

pOH = 2

pOH can also be calculated by using a different formula which is :

pOH = -log(OH^{-})

pOH = -log(0.01)

pOH = 2.


3 0
3 years ago
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