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3 years ago

The shadow of a groundhog ( or anything else ) is determined what?

Chemistry

1 answer:

Mekhanik [1.2K]3 years ago

6 0

The size, length, and height of the figure are the main factors which determine the shadow of a organism.

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A 12.82 g sample of a compound contains 4.09 g potassium (K), 3.71 g chlorine (Cl), and oxygen (O). Calculate the empirical form

Rina8888 [55]

The empirical formula of the compound is calculated as follows

first calculate the mass of oxygen= 12-(4.09 +3.71)= 5.02g

then calculate the moles of each element, moles = mass/ molar mass

moles of K = 4.09g/39 g/mol(molar mass of K) = 0.105 moles
moles of Cl = 3.71g/35.5 g/mol(molar mass of Cl) = 0.105 moles
moles of O = 5.02g/ 16g/mol(molar mass of O) = 0.314 moles

then calculate e mole ratio by dividing each mole by the smallest number of moles ( 0.105 moles)

K=0.105/0.105= 1
Cl=0.105 /0.105=1
O= 0.314/0.105=3

therefore the empirical formula = KClO3

7 0

3 years ago

If a student's unknown is a colorless liquid and its boiling point was measured to be about 78°C

maks197457 [2]

It might be ethanol. :)

3 0

3 years ago

Which condition applies when water boils at 100oC

VLD [36.1K]

An ambient pressure of 1 atm

5 0

3 years ago

Which of these is not an example of a molecule?

r-ruslan [8.4K]

Answer:

Explanation:

5 0

4 years ago

The energy required to ionize boron is 801 kJ/mol. You may want to reference (Pages 93 - 98) Section 2.5 while completing this p

earnstyle [38]

Answer:

The frequency is $f = 2,01 * 10^{15} \ Hz$

Explanation:

From the question we are told that

The energy required to ionize boron is $E_b = 801 KJ/mol$

Generally the ionization energy of boron pre atom is mathematically represented as

$E_a = \frac{E_b}{N_A}$

Here $N_A$ is the Avogadro's constant with value $N_A = 6.022*10^{23}$

$E_a = \frac{801}{6.022*10^{23}}$

=> $E_a = 1.330 *10^{-18} \ J/atom$

Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as

$E = hf = E_a$

=> $hf = E_a$

Here h is the Planks constant with value $h = 6.626 *10^{-34}$

$f = \frac{1.330 *10^{-18}}{ 6.626 *10^{-34}}$

=> $f = 2,01 * 10^{15} \ Hz$

8 0

3 years ago